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Our Home: Earth, a Unique Life Sustaining Planet - Asexual reproduction

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Asexual Reproduction: A mode of reproduction where a single parent produces offspring without the formation or fusion of gametes. The offspring are genetically identical to the parent, often called clones.

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Binary Fission: A method where the parent organism divides into two equal daughter cells. Example: AmoebaAmoeba. The process involves the division of the nucleus followed by the division of the cytoplasm.

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Budding: A small outgrowth called a 'bud' develops on the body of the parent. It matures and eventually detaches to become an independent individual. Example: HydraHydra and YeastYeast.

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Fragmentation: The body of a multicellular organism breaks into two or more fragments, and each fragment grows into a new individual. Example: SpirogyraSpirogyra.

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Spore Formation: Specialized structures called sporangia produce microscopic, tough, thick-walled cells called spores. Under favorable conditions, these spores germinate into new individuals. Example: RhizopusRhizopus (Bread Mould).

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Vegetative Propagation: A type of asexual reproduction in plants where new plants are produced from vegetative parts like roots, stems, or leaves. Example: BryophyllumBryophyllum (leaves), Ginger (rhizome/stem), and Sweet Potato (roots).

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Advantages of Asexual Reproduction: It is a faster method of multiplication, requires only one parent, and ensures that the desirable traits of the parent are preserved in the offspring (100%100\% genetic similarity).

📐Formulae

N=N0×2nN = N_0 \times 2^n

n=Ttn = \frac{T}{t}

Growth Rate=Number of individualsTime taken\text{Growth Rate} = \frac{\text{Number of individuals}}{\text{Time taken}}

💡Examples

Problem 1:

An AmoebaAmoeba cell undergoes binary fission every 2020 minutes. If you start with a single AmoebaAmoeba, calculate the total number of AmoebaAmoeba cells produced after 22 hours.

Solution:

120÷20=6120 \div 20 = 6 generations. Using the formula N=1×26N = 1 \times 2^6, we get N=64N = 64.

Explanation:

In binary fission, the number of organisms doubles in every generation. In 22 hours (120120 minutes), there are 66 intervals of 2020 minutes each. Starting with N0=1N_0 = 1 and n=6n = 6, the population becomes 262^6, which equals 6464 individuals.

Problem 2:

In a laboratory culture of YeastYeast, the population increases from 100100 cells to 800800 cells via budding. Determine the number of generations (nn) that have passed.

Solution:

800=100×2n  ⟹  8=2n  ⟹  23=2n  ⟹  n=3800 = 100 \times 2^n \implies 8 = 2^n \implies 2^3 = 2^n \implies n = 3

Explanation:

The population growth in asexual budding follows a geometric progression similar to binary fission for calculation purposes. Since the final population is 88 times the initial, and 88 is 22 raised to the power of 33, 33 generations have passed.

Asexual reproduction Class 8 Notes & Examples | CBSE Science