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Light: Mirrors and Lenses - What Are Spherical Mirrors?

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A spherical mirror is a mirror whose reflecting surface is a part of a hollow sphere of glass.

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A Concave Mirror has a reflecting surface that is curved inwards (towards the center of the sphere). It is called a converging mirror because light rays parallel to the principal axis converge at a single point after reflection.

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A Convex Mirror has a reflecting surface that is curved outwards. It is called a diverging mirror because light rays parallel to the principal axis appear to diverge from a point behind the mirror after reflection.

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The Pole (PP) is the geometric center of the reflecting surface of the spherical mirror.

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The Center of Curvature (CC) is the center of the hollow sphere of which the mirror is a part.

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The Radius of Curvature (RR) is the distance between the Pole and the Center of Curvature (PCPC).

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The Principal Axis is an imaginary straight line passing through the Pole (PP) and the Center of Curvature (CC) of the mirror.

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The Principal Focus (FF) is a point on the principal axis where rays of light parallel to the axis actually meet (in a concave mirror) or appear to diverge from (in a convex mirror) after reflection.

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The Focal Length (ff) is the distance between the Pole (PP) and the Principal Focus (FF) of the mirror.

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For spherical mirrors of small apertures, the radius of curvature is found to be twice the focal length, expressed as R=2fR = 2f.

📐Formulae

R=2fR = 2f

f=R2f = \frac{R}{2}

💡Examples

Problem 1:

If the radius of curvature of a concave mirror is 30 cm30\text{ cm}, what is its focal length?

Solution:

f=R2f = \frac{R}{2} f=302f = \frac{30}{2} f=15 cmf = 15\text{ cm}

Explanation:

The focal length of a spherical mirror is exactly half of its radius of curvature. Given R=30 cmR = 30\text{ cm}, we divide by 22 to find ff.

Problem 2:

A convex mirror has a focal length of 25 cm25\text{ cm}. Calculate its radius of curvature.

Solution:

R=2fR = 2f R=2×25R = 2 \times 25 R=50 cmR = 50\text{ cm}

Explanation:

The radius of curvature is twice the focal length. Since f=25 cmf = 25\text{ cm}, we multiply by 22 to find RR.

Problem 3:

An object is placed at the Center of Curvature of a concave mirror. If the distance of the Center of Curvature from the Pole is 40 cm40\text{ cm}, find the distance of the Focus from the Pole.

Solution:

R=40 cmf=402f=20 cm\begin{array}{r} R = 40\text{ cm} \\ f = \frac{40}{2} \\ \hline f = 20\text{ cm} \end{array}

Explanation:

The distance of the Center of Curvature from the Pole is the Radius of Curvature (RR). The distance of the Focus from the Pole is the Focal Length (ff). Using f=R2f = \frac{R}{2}, we get 20 cm20\text{ cm}.