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The World of Metals and Non-metals - Are Non-metals Essential in Everyday Life?

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Non-metals are elements that lack metallic properties such as luster, malleability, and ductility. They are generally poor conductors of heat and electricity (except for graphite, a form of Carbon).

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Essential for Life: Oxygen (O2O_{2}) is vital for the process of respiration in almost all living organisms. Carbon (CC) is the fundamental building block of all organic molecules like proteins, carbohydrates, and fats.

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Agricultural Importance: Non-metals like Nitrogen (NN), Phosphorus (PP), and Potassium (KK) are used in fertilizers to enhance soil fertility and crop yield. Nitrogen is also essential for protein synthesis.

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Water Purification: Chlorine (Cl2Cl_{2}) is used in the treatment of water to kill harmful bacteria and germs, making it safe for drinking.

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Health and Safety: Iodine (I2I_{2}) is used as an antiseptic in the form of 'Tincture of Iodine' to treat wounds. Sulfur (SS) and Phosphorus (PP) are used in the manufacturing of crackers and matchsticks.

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Atmospheric Composition: The Earth's atmosphere is primarily composed of non-metals, with Nitrogen (N2N_{2}) making up approximately 78%78\% and Oxygen (O2O_{2}) making up about 21%21\%.

📐Formulae

6CO2+6H2O→Sunlight/ChlorophyllC6H12O6+6O26CO_{2} + 6H_{2}O \xrightarrow{\text{Sunlight/Chlorophyll}} C_{6}H_{12}O_{6} + 6O_{2}

C6H12O6+6O2→6CO2+6H2O+EnergyC_{6}H_{12}O_{6} + 6O_{2} \rightarrow 6CO_{2} + 6H_{2}O + \text{Energy}

Concentration of N2 in air≈78%\text{Concentration of } N_{2} \text{ in air} \approx 78\%

💡Examples

Problem 1:

Calculate the approximate volume of Oxygen (O2O_{2}) in 500500 liters of air, given that Oxygen constitutes 21%21\% of the atmosphere.

Solution:

Volume of O2=21100×500=105 Liters\text{Volume of } O_{2} = \frac{21}{100} \times 500 = 105 \text{ Liters}

Explanation:

To find the volume of a specific gas in a mixture, we multiply the total volume by the percentage of that gas. Here, 500×0.21=105500 \times 0.21 = 105.

Problem 2:

A farmer has 150150 kg of fertilizer. If the fertilizer is 12%12\% Phosphorus (PP) by weight, how many kilograms of Phosphorus are present?

Solution:

150×0.1218.00\begin{array}{r} 150 \\ \times 0.12 \\ \hline 18.00 \end{array} Phosphorus content = 18 kg18 \text{ kg}.

Explanation:

The amount of Phosphorus is calculated by finding 12%12\% of the total mass (150 kg150 \text{ kg}). Using vertical multiplication: 150×12=1800150 \times 12 = 1800; placing the decimal for 0.120.12 gives 1818.

Problem 3:

Identify the non-metal used in the process of vulcanization of rubber to make it hard and durable.

Solution:

Sulfur (SS)

Explanation:

Sulfur is added to natural rubber in a process called vulcanization to improve its physical properties like elasticity and strength.