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Measurement of Time and Motion - Relationship between speed, distance, and time

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Speed is defined as the distance covered by an object in a unit of time. It indicates how fast or slow an object is moving.

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The standard SI unit of speed is meters per second (m/sm/s), though it is often expressed in kilometers per hour (km/hkm/h) for vehicles.

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Uniform Motion: When an object covers equal distances in equal intervals of time, it is said to be in uniform motion. The speed remains constant.

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Non-uniform Motion: When an object covers unequal distances in equal intervals of time, or its speed changes, it is in non-uniform motion.

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Average Speed: For non-uniform motion, we calculate the average speed by dividing the total distance traveled by the total time taken.

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Distance-Time Graph: A graphical representation where time is plotted on the xx-axis and distance on the yy-axis. A straight line indicates uniform speed, while a curved line indicates changing speed.

📐Formulae

Speed=DistanceTimeSpeed = \frac{Distance}{Time}

Distance=Speed×TimeDistance = Speed \times Time

Time=DistanceSpeedTime = \frac{Distance}{Speed}

Average Speed=Total Distance coveredTotal Time takenAverage\ Speed = \frac{Total\ Distance\ covered}{Total\ Time\ taken}

1 km/h=1000 m3600 s=518 m/s1\text{ km/h} = \frac{1000\text{ m}}{3600\text{ s}} = \frac{5}{18}\text{ m/s}

💡Examples

Problem 1:

A car travels a distance of 250 km250\text{ km} in 5 hours5\text{ hours}. Calculate its speed in km/hkm/h.

Solution:

Speed=250 km5 h=50 km/hSpeed = \frac{250\text{ km}}{5\text{ h}} = 50\text{ km/h}

Explanation:

Using the basic formula Speed=DistanceTimeSpeed = \frac{Distance}{Time}, we divide the total distance (250 km250\text{ km}) by the time taken (5 hours5\text{ hours}) to find the rate of motion.

Problem 2:

A cyclist moves with a speed of 15 km/h15\text{ km/h}. How much distance will he cover in 20 minutes20\text{ minutes}?

Solution:

First, convert time to hours: Time=2060 h=13 hTime = \frac{20}{60}\text{ h} = \frac{1}{3}\text{ h} Now, calculate distance: Distance=Speed×Time=15×13=5 kmDistance = Speed \times Time = 15 \times \frac{1}{3} = 5\text{ km}

Explanation:

Since the speed is in km/hkm/h, the time must be converted from minutes to hours by dividing by 6060. Then, the distance is found by multiplying speed and time.

Problem 3:

Convert a speed of 72 km/h72\text{ km/h} into m/sm/s.

Solution:

Speed=72×518 m/sSpeed = 72 \times \frac{5}{18}\text{ m/s} Speed=4×5=20 m/sSpeed = 4 \times 5 = 20\text{ m/s}

Explanation:

To convert from km/hkm/h to m/sm/s directly, we multiply the value by the conversion factor 518\frac{5}{18}.