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Heat Transfer in Nature - Radiation

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Radiation is the mode of heat transfer that does not require any material medium like solid, liquid, or gas.

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Heat from the Sun reaches the Earth through the vacuum of space primarily by the process of radiation.

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Every hot object, whether solid, liquid, or gas, emits heat radiation in all directions.

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When radiant heat falls on an object, a part of it is absorbed, a part is reflected, and a part may be transmitted. The temperature of the object increases due to the absorbed part of the heat.

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Dark-colored surfaces are better absorbers and better radiators of heat than light-colored or shiny surfaces.

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In summers, we prefer light-colored clothes because they reflect most of the heat that falls on them, keeping us cool. In winters, we wear dark-colored clothes as they absorb more heat from the surroundings.

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The temperature of a body is often measured in degrees Celsius (∘C^{\circ}C) or Kelvin (KK).

📐Formulae

Total Heat Energy=Heat Absorbed+Heat Reflected+Heat TransmittedTotal\ Heat\ Energy = Heat\ Absorbed + Heat\ Reflected + Heat\ Transmitted

Net Heat Exchange∝(Tobject−Tsurroundings)Net\ Heat\ Exchange \propto (T_{object} - T_{surroundings})

💡Examples

Problem 1:

Suppose you have two identical metal containers, one painted black and the other painted white. If both are filled with water at 90∘C90^{\circ}C and left in a room at 25∘C25^{\circ}C, which one will cool down faster?

Solution:

The container painted black will cool down faster.

Explanation:

Dark-colored surfaces are better radiators of heat than light-colored surfaces. Since the black container is a better radiator, it will lose heat to the surroundings more quickly through radiation, leading to a faster drop in temperature.

Problem 2:

Calculate the difference in temperature between two bodies if Body A is at 85∘C85^{\circ}C and Body B is at 32∘C32^{\circ}C.

Solution:

85∘C−32∘C=53∘C85^{\circ}C - 32^{\circ}C = 53^{\circ}C

Explanation:

To find the temperature difference, we subtract the lower temperature from the higher temperature using simple subtraction: 85−3253\begin{array}{r} 85 \\ - 32 \\ \hline 53 \end{array}