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Beyond Earth - Stars and Constellations

Grade 6CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Stars are massive celestial bodies made of hot gases (mostly Hydrogen and Helium) that emit their own heat and light. The Sun is the nearest star to Earth.

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A constellation is a group of stars that appears to form a recognizable pattern or shape in the night sky. Examples include Ursa Major (The Great Bear), Orion (The Hunter), and Cassiopeia.

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The Pole Star (Polaris) is a special star that remains fixed in one position in the sky, directly above the North Pole. It has been used for centuries by travelers to find the North direction.

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The distance between celestial bodies is extremely large, so it is measured in a unit called a 'Light Year'. One light year is the distance traveled by light in one year at a speed of approximately 3×105 km/s3 \times 10^{5} \text{ km/s}.

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Ursa Major contains a group of seven bright stars called the Saptarishi. The two stars at the end of this pattern are called 'Pointer Stars' because they point towards the Pole Star.

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The Sun appears larger and brighter than other stars only because it is much closer to Earth. The distance of the Sun from Earth is approximately 1.5×108 km1.5 \times 10^{8} \text{ km}.

📐Formulae

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

1 Light Year≈9.46×1012 km1 \text{ Light Year} \approx 9.46 \times 10^{12} \text{ km}

Speed of Light (c)≈300,000 km/s\text{Speed of Light (c)} \approx 300,000 \text{ km/s}

Time taken by Sunlight to reach Earth≈8 minutes 20 seconds\text{Time taken by Sunlight to reach Earth} \approx 8 \text{ minutes } 20 \text{ seconds}

💡Examples

Problem 1:

If Star A is 1010 light years away and Star B is 2222 light years away from Earth, calculate the difference in their distances in light years using vertical subtraction.

Solution:

22−10=12 light years22 - 10 = 12 \text{ light years}

Explanation:

To find how much further Star B is compared to Star A, we subtract the distance of Star A from Star B: 22−1012\begin{array}{r} 22 \\ - 10 \\ \hline 12 \end{array}

Problem 2:

Light from the Sun takes about 500500 seconds to reach Earth. If light travels at 300,000 km/s300,000 \text{ km/s}, what is the approximate distance of the Sun?

Solution:

150,000,000 km150,000,000 \text{ km}

Explanation:

Using the formula Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}, we multiply 300,000 km/s300,000 \text{ km/s} by 500 s500 \text{ s}. 300,000×500=150,000,000300,000 \times 500 = 150,000,000

Problem 3:

A scientist observes two constellations. Constellation X has 77 visible stars and Constellation Y has 1515 visible stars. What is the total number of stars observed?

Solution:

22 stars22 \text{ stars}

Explanation:

To find the total, we add the number of stars in both constellations: 15+722\begin{array}{r} 15 \\ + 7 \\ \hline 22 \end{array}

Stars and Constellations Class 6 Notes & Examples