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Journey of a River - Dams, Projects, and Human Use of Rivers

Grade 5CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A river's journey consists of three main stages: the Upper Course (steep mountains), the Middle Course (meanders in plains), and the Lower Course (deltas and mouth).

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A Dam is a massive barrier built across a river to hold back water, creating a reservoir. The stored water in the reservoir possesses Potential Energy (PEPE).

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Hydroelectricity is generated when falling water from a height turns turbines. The energy transformation is: Potential Energy→Kinetic Energy→Electrical Energy\text{Potential Energy} \to \text{Kinetic Energy} \to \text{Electrical Energy}.

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Multipurpose Projects are river valley schemes designed for multiple benefits such as Irrigation+Flood Control+Electricity Generation+Fish Breeding\text{Irrigation} + \text{Flood Control} + \text{Electricity Generation} + \text{Fish Breeding}.

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The Bhakra Nangal Project (built on the Satluj River) and the Hirakud Dam (built on the Mahanadi River) are significant examples of human engineering in India.

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Human Use of Rivers: Rivers provide water for domestic use, agriculture via canals, transportation (navigation), and industrial cooling.

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River Pollution: Human activities like dumping sewage, industrial effluents, and religious offerings introduce harmful chemicals and reduce the level of Dissolved Oxygen (O2O_2) in the water.

📐Formulae

Total Water Flow=Volume of Water÷Time\text{Total Water Flow} = \text{Volume of Water} \div \text{Time}

Energy Transformation: PE→falling waterKE→turbineElectrical Energy\text{Energy Transformation: } PE \xrightarrow{\text{falling water}} KE \xrightarrow{\text{turbine}} \text{Electrical Energy}

Water Storage Balance: Sfinal=Sinitial+(Inflow−Outflow)\text{Water Storage Balance: } S_{final} = S_{initial} + (\text{Inflow} - \text{Outflow})

💡Examples

Problem 1:

A dam reservoir has a capacity of 8,00,00,0008,00,00,000 cubic meters. If 3,45,67,8923,45,67,892 cubic meters of water is released for irrigation, how much water remains in the reservoir?

Solution:

80000000−3456789245432108\begin{array}{r} 80000000 \\ -34567892 \\ \hline 45432108 \end{array}

Explanation:

To find the remaining water, we subtract the released water from the total capacity using the formula Remaining Water=Total Capacity−Released Water\text{Remaining Water} = \text{Total Capacity} - \text{Released Water}. The result is 4,54,32,1084,54,32,108 cubic meters.

Problem 2:

If a hydroelectric plant produces 1500 MW1500\text{ MW} in the morning and 1250 MW1250\text{ MW} in the evening, what is the total power generated?

Solution:

1500+12502750\begin{array}{r} 1500 \\ +1250 \\ \hline 2750 \end{array}

Explanation:

The total power is the sum of power generated during both sessions: 1500+1250=2750 MW1500 + 1250 = 2750\text{ MW}.