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Magnetic Effects of Electric Current - Field due to a current carrying conductor

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Hans Christian Oersted discovered that an electric current flowing through a metallic conductor produces a magnetic field around it.

The magnetic field lines around a straight current-carrying conductor are concentric circles whose centers lie on the wire. The direction of these field lines is given by the Right-Hand Thumb Rule.

Right-Hand Thumb Rule: Imagine holding a current-carrying straight conductor in your right hand such that the thumb points towards the direction of current (II); then your fingers will wrap around the conductor in the direction of the field lines of the magnetic field (BB).

The magnitude of the magnetic field (BB) produced by a straight wire at a given point is directly proportional to the current (II) passing through the wire and inversely proportional to the distance (rr) from the wire: BIrB \propto \frac{I}{r}.

For a circular loop, the magnetic field lines are nearly circular near the wire but appear as straight lines at the center of the loop. The magnetic field produced by a coil of nn turns is nn times as large as that produced by a single turn, because the current in each circular turn has the same direction and the fields then just add up.

A solenoid is a coil of many circular turns of insulated copper wire wrapped closely in the shape of a cylinder. The magnetic field pattern inside a solenoid is uniform and consists of parallel straight lines, indicating that the magnetic field is the same at all points inside the solenoid.

The strength of the magnetic field produced by a solenoid depends on the number of turns per unit length (nn) and the current (II) flowing through it: BnIB \propto nI.

📐Formulae

BIB \propto I

B1rB \propto \frac{1}{r}

Btotal=n×Bsingle_turnB_{total} = n \times B_{single\_turn}

BnIB \propto n \cdot I

💡Examples

Problem 1:

A current-carrying straight conductor is placed vertically. If the current flows from bottom to top, determine the direction of the magnetic field at a point directly to the North of the wire.

Solution:

According to the Right-Hand Thumb Rule, if the thumb points upwards (direction of current II), the fingers curl in the anti-clockwise direction when viewed from above. At a point to the North of the wire, the magnetic field (BB) will point towards the West.

Explanation:

The magnetic field lines form concentric circles. Applying the rule at the North position, the tangent to the circle points West.

Problem 2:

The magnetic field strength at a distance rr from a straight wire is BB. If the current in the wire is tripled and the distance from the wire is doubled, calculate the new magnetic field strength BB'.

Solution:

Given BIrB \propto \frac{I}{r}. If new current I=3II' = 3I and new distance r=2rr' = 2r, then B3I2rB' \propto \frac{3I}{2r}. This implies B=32B=1.5BB' = \frac{3}{2} B = 1.5B.

Explanation:

Since BB is directly proportional to II and inversely proportional to rr, the factors multiply to give the new field strength.

Field due to a current carrying conductor Revision - Class 10 Science CBSE