Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
A Zener Diode is a heavily doped junction diode designed to operate specifically in the reverse breakdown region. Because of heavy doping, the depletion layer is very thin (), leading to a high electric field even at low voltages.
The Zener Breakdown occurs when the high electric field across the junction pulls electrons out of the covalent bonds, creating a large number of charge carriers. It is used for Voltage Regulation because the voltage across the diode remains constant () even if the current through it changes significantly.
A Light Emitting Diode (LED) is a forward-biased junction that emits spontaneous radiation. When the diode is forward biased, electrons from the -side and holes from the -side move toward the junction and recombine. The energy released during recombination is emitted as photons if the energy gap is in the visible or infrared range.
For an LED, the wavelength of light emitted is given by . The color of light depends on the semiconductor material used (e.g., for red/yellow light).
A Photodiode is a special purpose junction diode operated in reverse bias. It is used to detect optical signals. When light of frequency such that falls on the junction, it creates electron-hole pairs near the depletion region, increasing the reverse saturation current.
In a photodiode, the reverse current is directly proportional to the intensity of incident light. It is operated in reverse bias because the fractional change in minority carrier current is much more easily measurable than the fractional change in majority carrier current.
📐Formulae
💡Examples
Problem 1:
A Zener diode with a breakdown voltage is used as a voltage regulator in a circuit. If the input voltage varies between and and the series resistance is , calculate the maximum current through the Zener diode, assuming the load resistance is very high (open circuit).
Solution:
Given , . The maximum current occurs when the input voltage is at its maximum, . Since is high, , thus . Using the formula , we get: .
Explanation:
In a Zener regulator, the voltage across the Zener remains fixed at . The excess voltage drops across the series resistor . The current is maximum when the source voltage is at its peak.
Problem 2:
A semiconductor has a bandgap of . Is it suitable for fabricating an LED that emits visible light?
Solution:
The wavelength of light emitted is . Using the approximation , we get .
Explanation:
The visible spectrum ranges from approximately to . Since falls within this range (corresponding to violet/blue light), the material is suitable for a visible light LED.