Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Electromotive Force (EMF): The potential difference across the terminals of a cell when no current is being drawn from it (). It is denoted by .
Terminal Potential Difference (): The potential difference across the terminals of a cell when current flows through the circuit. It is related to EMF by , where is the internal resistance.
Internal Resistance (): The resistance offered by the electrolyte and electrodes inside a cell to the flow of current. It depends on the nature of the electrolyte, area of electrodes, and distance between them.
Cells in Series: When cells are connected in series, the equivalent EMF is the sum of individual EMFs () and equivalent internal resistance is .
Cells in Parallel: For two cells connected in parallel, the equivalent EMF is and the equivalent internal resistance is .
Potentiometer Principle: The potential drop across any portion of a wire of uniform cross-section is directly proportional to the length of that portion (), provided a constant current flows through it. This gives the potential gradient .
Comparison of EMFs: Two cells of EMFs and can be compared using a potentiometer by finding their respective balancing lengths and , giving .
Measurement of Internal Resistance: A potentiometer can measure the internal resistance of a cell using the formula , where is the open circuit balancing length and is the closed circuit balancing length with external resistance .
Sensitivity of Potentiometer: A potentiometer is more sensitive if it has a smaller potential gradient . This can be achieved by increasing the length of the potentiometer wire or decreasing the current in the primary circuit.
📐Formulae
💡Examples
Problem 1:
A cell of EMF is balanced against a length of on a potentiometer wire. When a resistance of is connected across the cell, the balancing length becomes . Calculate the internal resistance of the cell.
Solution:
Given , , and . Using the formula , we get .
Explanation:
The internal resistance is found by comparing the balancing length of the cell in an open circuit () to the balancing length when shunted by a known resistor ().
Problem 2:
In a potentiometer arrangement, a cell of EMF gives a balance point at length of the wire. If the cell is replaced by another cell and the balance point shifts to , what is the EMF of the second cell?
Solution:
Using the principle , we have , , and . Therefore, .
Explanation:
Since the potential gradient is constant for the same potentiometer setup, the ratio of the EMFs is equal to the ratio of their respective balancing lengths.