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Probability - Relative and Expected Frequencies

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Relative frequency, also known as experimental probability, is an estimate of the probability of an event based on the results of an experiment.

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The relative frequency of an event is calculated by dividing the number of times the event occurs by the total number of trials conducted.

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As the total number of trials (nn) increases, the relative frequency becomes a more reliable estimate of the theoretical probability.

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Expected frequency represents the number of times an event is predicted to occur over a specific number of trials, based on its known probability.

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For any experiment, the sum of the relative frequencies of all possible outcomes must equal 11.

📐Formulae

Relative Frequency=Frequency of EventTotal Number of TrialsRelative\ Frequency = \frac{\text{Frequency of Event}}{\text{Total Number of Trials}}

Expected Frequency=n×P(A)Expected\ Frequency = n \times P(A)

Estimated Probability≈Number of successful trialsTotal number of trials\text{Estimated Probability} \approx \frac{\text{Number of successful trials}}{\text{Total number of trials}}

💡Examples

Problem 1:

A biased coin is flipped 200200 times, and it lands on heads 124124 times. Calculate the relative frequency of the coin landing on heads.

Solution:

Relative Frequency=124200Relative\ Frequency = \frac{124}{200} Relative Frequency=0.62Relative\ Frequency = 0.62

Explanation:

The relative frequency is found by taking the frequency of the specific outcome (124124) and dividing it by the total number of experiments (200200).

Problem 2:

The probability that a computer component is faulty is 0.020.02. In a batch of 50005000 components, how many would you expect to be faulty?

Solution:

Expected Frequency=n×P(faulty)Expected\ Frequency = n \times P(\text{faulty}) Expected Frequency=5000×0.02Expected\ Frequency = 5000 \times 0.02 Expected Frequency=100Expected\ Frequency = 100

Explanation:

To find the expected frequency, multiply the total number of trials (n=5000n = 5000) by the probability of the event (P=0.02P = 0.02).

Problem 3:

A bag contains red, blue, and yellow marbles. The relative frequency of picking a red marble is 0.40.4 and a blue marble is 0.250.25. If a marble is picked 8080 times, how many times would you expect to pick a yellow marble?

Solution:

P(yellow)=1−(0.4+0.25)P(\text{yellow}) = 1 - (0.4 + 0.25) P(yellow)=1−0.65=0.35P(\text{yellow}) = 1 - 0.65 = 0.35 Expected Frequency=80×0.35=28Expected\ Frequency = 80 \times 0.35 = 28

Explanation:

First, find the probability of the missing outcome by subtracting the known relative frequencies from 11. Then, multiply this probability by the total number of trials to find the expected frequency.

Relative and Expected Frequencies Grade 9 Notes & Examples