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Algebraic Expressions and Identities - Standard Identities: (a+b)², (a-b)², (a+b)(a-b)

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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An algebraic identity is an equality that holds true for all possible values of its variables. Unlike a standard equation which is only true for specific values, identities like (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2 are universal tools used to simplify complex products and factorize expressions.

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The identity (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2 (Square of a Sum) can be visualized as the total area of a large square with side length (a+b)(a+b). This square is composed of four smaller regions: one square with area a2a^2, another square with area b2b^2, and two identical rectangles, each with an area of abab. Adding these areas together gives the complete identity.

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The identity (a−b)2=a2−2ab+b2(a-b)^2 = a^2 - 2ab + b^2 (Square of a Difference) represents the area of a square with side length (a−b)(a-b). Geometrically, this is equivalent to taking a large square of area a2a^2, removing two rectangular strips of area abab from the edges, and then adding back the small square area b2b^2 that was subtracted twice during the process.

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The identity (a+b)(a−b)=a2−b2(a+b)(a-b) = a^2 - b^2 (Difference of Squares) describes the product of the sum and the difference of the same two terms. Visually, if you take a square of area a2a^2 and cut out a smaller square of area b2b^2 from its corner, the remaining L-shaped area can be sliced and rearranged into a single rectangle with dimensions (a+b)(a+b) and (a−b)(a-b).

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When applying identities to terms with coefficients, such as (3x+4y)2(3x + 4y)^2, it is essential to square the entire term. For instance, the term a2a^2 in this case is (3x)2(3x)^2, which evaluates to 9x29x^2 because both the number 33 and the variable xx must be squared. A common mistake is writing 3x23x^2 instead of 9x29x^2.

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Identities are powerful tools for mental arithmetic. For example, the square of 102102 can be calculated as (100+2)2(100 + 2)^2 using the sum identity, and the product 98times10298 \\times 102 can be solved as (100−2)(100+2)(100 - 2)(100 + 2) using the difference of squares identity, significantly simplifying the multiplication process.

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Pay close attention to signs: In the identity (a−b)2=a2−2ab+b2(a-b)^2 = a^2 - 2ab + b^2, only the middle term (the product term) is negative. The terms a2a^2 and b2b^2 are always positive because the square of any real number, whether positive or negative, is always positive.

📐Formulae

(a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2

(a−b)2=a2−2ab+b2(a-b)^2 = a^2 - 2ab + b^2

(a+b)(a−b)=a2−b2(a+b)(a-b) = a^2 - b^2

💡Examples

Problem 1:

Expand (3x−5y)2(3x - 5y)^2 using a standard identity.

Solution:

  1. Identify the terms: a=3xa = 3x and b=5yb = 5y.
  2. Choose the identity: (a−b)2=a2−2ab+b2(a-b)^2 = a^2 - 2ab + b^2.
  3. Substitute the values: (3x−5y)2=(3x)2−2(3x)(5y)+(5y)2(3x - 5y)^2 = (3x)^2 - 2(3x)(5y) + (5y)^2.
  4. Simplify: 9x2−30xy+25y29x^2 - 30xy + 25y^2.

Explanation:

We identify this as a 'square of a difference'. By substituting 3x3x for aa and 5y5y for bb into the identity, we square the coefficients and the variables separately to arrive at the final trinomial.

Problem 2:

Evaluate 103times97103 \\times 97 using a suitable algebraic identity.

Solution:

  1. Express the numbers as (a+b)(a+b) and (a−b)(a-b): 103=100+3103 = 100 + 3 and 97=100−397 = 100 - 3.
  2. Identify the identity: (a+b)(a−b)=a2−b2(a+b)(a-b) = a^2 - b^2, where a=100a = 100 and b=3b = 3.
  3. Substitute: (100+3)(100−3)=1002−32(100 + 3)(100 - 3) = 100^2 - 3^2.
  4. Calculate: 10000−9=999110000 - 9 = 9991.

Explanation:

Since both numbers are equidistant from 100100, we use the Difference of Squares identity. This allows us to replace a complex multiplication with a simple subtraction of two squares.