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Ratio and Proportion - Direct and Inverse Variation

Grade 7ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Variation is the functional relationship between two quantities. If a change in one quantity causes a corresponding change in another, the two quantities are said to be in variation.

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Direct Variation: Two quantities xx and yy are in direct variation if they increase or decrease together such that the ratio yx\frac{y}{x} remains constant. Visually, if you plot xx and yy on a coordinate plane, the points will lie on a straight line that passes through the origin (0,0)(0,0), representing a constant rate of growth.

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The Constant of Variation (kk) for direct variation is defined by the equation y=kxy = kx. This kk represents the slope of the line in a visual graph; the steeper the line, the larger the value of kk.

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Inverse Variation: Two quantities xx and yy are in inverse variation if an increase in xx leads to a proportional decrease in yy (and vice versa). Visually, the graph of an inverse variation is a smooth curve called a hyperbola that gets closer and closer to the xx and yy axes but never actually touches them.

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In Inverse Variation, the product of the two variables remains constant: x×y=kx \times y = k. This means that as one value gets very large, the other must get very small to keep the product the same.

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To solve variation problems, you can use the Proportion Method. For direct variation, we use the proportion x1y1=x2y2\frac{x_1}{y_1} = \frac{x_2}{y_2}, and for inverse variation, we use the equation x1y1=x2y2x_1 y_1 = x_2 y_2.

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Identifying Variation: Always check the relationship first. For example, the number of articles and their total cost is Direct Variation (more articles = more cost), while the number of workers and the time taken to finish a task is Inverse Variation (more workers = less time).

📐Formulae

Direct Variation: y=kxy = kx where kk is a constant

Constant of Direct Variation: k=yxk = \frac{y}{x}

Direct Variation Proportion: x1y1=x2y2\frac{x_1}{y_1} = \frac{x_2}{y_2}

Inverse Variation: y=kxy = \frac{k}{x} or xy=kxy = k where kk is a constant

Inverse Variation Equation: x1y1=x2y2x_1 y_1 = x_2 y_2

💡Examples

Problem 1:

If 1515 notebooks cost Rs.450Rs. 450, find the cost of 2424 such notebooks.

Solution:

Step 1: Identify the variation. Since more notebooks will cost more money, this is a case of Direct Variation. Step 2: Let x1=15x_1 = 15, y1=450y_1 = 450, and x2=24x_2 = 24. Let the unknown cost be y2y_2. Step 3: Use the formula x1y1=x2y2\frac{x_1}{y_1} = \frac{x_2}{y_2}. 15450=24y2\frac{15}{450} = \frac{24}{y_2} Step 4: Solve for y2y_2 by cross-multiplication: 15×y2=24×45015 \times y_2 = 24 \times 450 y2=24×45015y_2 = \frac{24 \times 450}{15} y2=24×30=720y_2 = 24 \times 30 = 720. Final Answer: The cost of 2424 notebooks is Rs.720Rs. 720.

Explanation:

We used the direct variation ratio because the cost per unit remains constant regardless of the number of items bought.

Problem 2:

A group of 1212 men can complete a piece of work in 88 days. How many days will it take 1616 men to complete the same work?

Solution:

Step 1: Identify the variation. More men will take less time to complete the same work, so this is Inverse Variation. Step 2: Let x1=12x_1 = 12 (men), y1=8y_1 = 8 (days), and x2=16x_2 = 16 (men). Let the unknown days be y2y_2. Step 3: Use the inverse variation formula x1y1=x2y2x_1 y_1 = x_2 y_2. 12×8=16×y212 \times 8 = 16 \times y_2 Step 4: Solve for y2y_2: 96=16×y296 = 16 \times y_2 y2=9616y_2 = \frac{96}{16} y2=6y_2 = 6. Final Answer: It will take 1616 men 66 days to complete the work.

Explanation:

In inverse variation, the total 'man-days' (the product of people and time) stays constant. Here, the total work is 9696 man-days.