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Expressions using Letter-Numbers - Revisiting Arithmetic Expressions

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A variable is a quantity that can take various numerical values; its value is not fixed. We represent variables using letters like x,y,z,l,m,nx, y, z, l, m, n.

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Constants are values that remain fixed, such as 5,−10,125, -10, \frac{1}{2}.

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Algebraic expressions are formed by combining variables and constants using arithmetic operations: addition (++), subtraction (−-), multiplication (×\times), and division (÷\div).

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The value of an expression depends on the value assigned to the variable. For example, if x=2x = 2, then 4x=84x = 8.

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We use variables to express general rules in geometry. For instance, if ll is the side of a square, its perimeter is 4l4l.

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Variables are used to express properties of numbers, such as the Commutative Property: a+b=b+aa + b = b + a or a×b=b×aa \times b = b \times a.

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The Distributive Property allows us to express a(b+c)a(b + c) as ab+acab + ac.

📐Formulae

P=4s (Perimeter of a square with side s)P = 4s \text{ (Perimeter of a square with side } s\text{)}

P=3l (Perimeter of an equilateral triangle with side l)P = 3l \text{ (Perimeter of an equilateral triangle with side } l\text{)}

a+b=b+a (Commutative property of addition)a + b = b + a \text{ (Commutative property of addition)}

a×(b+c)=ab+ac (Distributive property)a \times (b + c) = ab + ac \text{ (Distributive property)}

d=2r (Diameter of a circle with radius r)d = 2r \text{ (Diameter of a circle with radius } r\text{)}

💡Examples

Problem 1:

Write an algebraic expression for the statement: '10 subtracted from the product of 3 and yy'.

Solution:

3y−103y - 10

Explanation:

The 'product of 3 and yy' is written as 3×y3 \times y or 3y3y. '10 subtracted from' this product means we take 3y3y and subtract 1010 from it, resulting in 3y−103y - 10.

Problem 2:

The side of a regular pentagon is denoted by ss. Express the perimeter of the pentagon using ss.

Solution:

5s5s

Explanation:

A regular pentagon has 5 equal sides. The perimeter is the sum of all sides: s+s+s+s+s=5×s=5ss + s + s + s + s = 5 \times s = 5s.

Problem 3:

Evaluate the expression 2n+72n + 7 when n=15n = 15.

Solution:

3737

Explanation:

Substitute n=15n = 15 into the expression: 2(15)+72(15) + 7. First, calculate 2×15=302 \times 15 = 30. Then add 77: 30+7=3730 + 7 = 37. For the addition: 30+737\begin{array}{r} 30 \\ +7 \\ \hline 37 \end{array}