krit.club logo

Knowing Our Numbers - Using Brackets

Grade 6CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

Brackets are used to group numbers and operations together, indicating that the operations inside the brackets must be performed first. For example, in the expression (10+5)×2(10 + 5) \times 2, we first add 1010 and 55 to get 1515, then multiply by 22.

•

The use of brackets helps in simplifying calculations by breaking down large numbers. For instance, multiplying 102×7102 \times 7 can be visualized as splitting a large area into two smaller, manageable rectangles: one of 100×7100 \times 7 and another of 2×72 \times 7.

•

The Distributive Property is the core concept behind using brackets. It allows us to distribute a multiplier to each term inside the bracket, such as a×(b+c)=(a×b)+(a×c)a \times (b + c) = (a \times b) + (a \times c).

•

Brackets help maintain the correct order of operations. When you see an expression like 10×(2+3)10 \times (2 + 3), the brackets act as a 'priority wall,' ensuring the addition happens before the multiplication, which would otherwise be performed in a different order under standard BODMAS rules.

•

Expansion of brackets is a process where we remove brackets by multiplying the term outside with every term inside. If we have (10+2)×(10+3)(10 + 2) \times (10 + 3), we can think of it as distributing the first group over the second, resulting in a sum of four separate products.

•

Using brackets makes mental math easier. To calculate 9×1089 \times 108, we can visualize it as 9×(100+8)9 \times (100 + 8). This transforms one difficult multiplication into two simple ones: 900900 and 7272, which are then summed to find the total.

📐Formulae

a×(b+c)=a×b+a×ca \times (b + c) = a \times b + a \times c

a×(b−c)=a×b−a×ca \times (b - c) = a \times b - a \times c

(a+b)×(c+d)=a×(c+d)+b×(c+d)(a + b) \times (c + d) = a \times (c + d) + b \times (c + d)

(a+b)×(c+d)=ac+ad+bc+bd(a + b) \times (c + d) = ac + ad + bc + bd

💡Examples

Problem 1:

Evaluate 6×1076 \times 107 using the expansion of brackets.

Solution:

Step 1: Write 107107 as (100+7)(100 + 7). So, the expression becomes 6×(100+7)6 \times (100 + 7). Step 2: Use the distributive property to multiply 66 with both terms inside the bracket: (6×100)+(6×7)(6 \times 100) + (6 \times 7). Step 3: Calculate the individual products: 600+42600 + 42. Step 4: Add the results: 642642.

Explanation:

We simplified the multiplication by breaking 107107 into a sum of a hundred and a single-digit number, then distributed the 66 over the addition.

Problem 2:

Find the value of 102×103102 \times 103 using brackets.

Solution:

Step 1: Expand both numbers: (100+2)×(100+3)(100 + 2) \times (100 + 3). Step 2: Multiply the first bracket by each term of the second: (100+2)×100+(100+2)×3(100 + 2) \times 100 + (100 + 2) \times 3. Step 3: Expand again: (100×100)+(2×100)+(100×3)+(2×3)(100 \times 100) + (2 \times 100) + (100 \times 3) + (2 \times 3). Step 4: Calculate each part: 10000+200+300+610000 + 200 + 300 + 6. Step 5: Sum all values: 1050610506.

Explanation:

By expanding both factors into (100+n)(100 + n) forms, we converted a multi-digit multiplication problem into a series of simple multiplications and additions.