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Mathematical Reasoning - Statements and Logical Connectives

Grade 11ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A Mathematical Statement is a declarative sentence which is either definitely true or definitely false, but not both. For example, 'The square of 4 is 16' is a statement, while 'Give me that book' is a command and not a mathematical statement. Visually, imagine a binary switch that can only be in the 'ON' (True) or 'OFF' (False) position, never in between.

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Negation of a statement pp is denoted by ∼p\sim p. If pp is true, ∼p\sim p is false; if pp is false, ∼p\sim p is true. This can be visualized as a simple two-column Truth Table where the input column pp lists values T,FT, F and the output column ∼p\sim p flips them to F,TF, T.

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Compound Statements are formed by combining two or more simple statements using logical connectives like 'and' (wedge\\wedge), 'or' (vee\\vee), 'if...then' (Rightarrow\\Rightarrow), and 'if and only if' (Leftrightarrow\\Leftrightarrow). Visually, this creates a branching structure or a Truth Table with 2n2^n rows, where nn is the number of simple statements.

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Conjunction (pwedgeqp \\wedge q) is true only when both component statements pp and qq are true. In a Venn Diagram representation, this corresponds to the intersection of two sets, where the shaded area represents only the region shared by both pp and qq.

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Disjunction (pveeqp \\vee q) is false only when both component statements pp and qq are false. In all other cases, it is true. Visually, in a Venn Diagram, this is the union of two sets, covering all regions belonging to pp, qq, or both.

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A Conditional Statement pRightarrowqp \\Rightarrow q (read as 'If pp, then qq') is false only in one specific case: when the antecedent pp is true and the consequent qq is false (TRightarrowFT \\Rightarrow F). Visually, think of a contract: the contract is broken (False) only if the first party fulfills their duty (pp is TT) but the second party does not deliver (qq is FF).

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Biconditional Statement pLeftrightarrowqp \\Leftrightarrow q (read as 'pp if and only if qq') is true when both pp and qq have the same truth value (both True or both False). In a Truth Table, the resulting column shows 'True' for the (T,T)(T, T) and (F,F)(F, F) rows and 'False' otherwise.

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Tautology and Contradiction: A compound statement that is always true regardless of the truth values of its components is a Tautology. Conversely, a statement that is always false is a Contradiction. Visually, a Tautology is a Truth Table column filled entirely with 'T', while a Contradiction is a column filled entirely with 'F'.

📐Formulae

Negation of Conjunction (De Morgan's Law): ∼(pwedgeq)equivsimpveesimq\sim(p \\wedge q) \\equiv \\sim p \\vee \\sim q

Negation of Disjunction (De Morgan's Law): ∼(pveeq)equivsimpwedgesimq\sim(p \\vee q) \\equiv \\sim p \\wedge \\sim q

Conditional as Disjunction: pRightarrowqequivsimpveeqp \\Rightarrow q \\equiv \\sim p \\vee q

Negation of Conditional: ∼(pRightarrowq)equivpwedgesimq\sim(p \\Rightarrow q) \\equiv p \\wedge \\sim q

Contrapositive: The contrapositive of pRightarrowqp \\Rightarrow q is ∼qRightarrowsimp\sim q \\Rightarrow \\sim p (Logically Equivalent)

Converse: The converse of pRightarrowqp \\Rightarrow q is qRightarrowpq \\Rightarrow p

Inverse: The inverse of pRightarrowqp \\Rightarrow q is ∼pRightarrowsimq\sim p \\Rightarrow \\sim q

Biconditional Identity: pLeftrightarrowqequiv(pRightarrowq)wedge(qRightarrowp)p \\Leftrightarrow q \\equiv (p \\Rightarrow q) \\wedge (q \\Rightarrow p)

💡Examples

Problem 1:

Construct a truth table for the statement (pwedgeq)Rightarrowp(p \\wedge q) \\Rightarrow p and determine if it is a tautology.

Solution:

  1. List all combinations of pp and qq:
    Row 1: p=T,q=Tp=T, q=T
    Row 2: p=T,q=Fp=T, q=F
    Row 3: p=F,q=Tp=F, q=T
    Row 4: p=F,q=Fp=F, q=F \
  2. Evaluate (pwedgeq)(p \\wedge q):
    Row 1: TwedgeT=TT \\wedge T = T
    Row 2: TwedgeF=FT \\wedge F = F
    Row 3: FwedgeT=FF \\wedge T = F
    Row 4: FwedgeF=FF \\wedge F = F \
  3. Evaluate (pwedgeq)Rightarrowp(p \\wedge q) \\Rightarrow p:
    Row 1: TRightarrowT=TT \\Rightarrow T = T
    Row 2: FRightarrowT=TF \\Rightarrow T = T
    Row 3: FRightarrowF=TF \\Rightarrow F = T
    Row 4: FRightarrowF=TF \\Rightarrow F = T

Explanation:

Since the final column of the truth table consists only of 'T' (True) values for all possible combinations of pp and qq, the statement (pwedgeq)Rightarrowp(p \\wedge q) \\Rightarrow p is a Tautology.

Problem 2:

Write the negation of the statement: 'If it rains, then the match will be cancelled.'

Solution:

  1. Identify component statements:
    pp: It rains.
    qq: The match will be cancelled. \
  2. Represent the original statement: pRightarrowqp \\Rightarrow q. \
  3. Use the negation formula: sim(pRightarrowq)equivpwedgesimq\\sim(p \\Rightarrow q) \\equiv p \\wedge \\sim q. \
  4. Translate back to English: 'It rains and the match will not be cancelled.'

Explanation:

To negate a conditional statement 'If p then q', we state that 'p' occurs but 'q' does not. This follows the logical equivalence sim(pRightarrowq)equivpwedgesimq\\sim(p \\Rightarrow q) \\equiv p \\wedge \\sim q.