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Coordination Compounds - Crystal Field Theory (CFT)

Grade 12ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Crystal Field Theory (CFT) treats the interaction between the metal ion and the ligands as a purely electrostatic one, where ligands are considered as point charges.

In a free metal ion, all five dd-orbitals are degenerate (have equal energy). In an octahedral field, these split into two sets: t2gt_{2g} (dxy,dyz,dzxd_{xy}, d_{yz}, d_{zx}) of lower energy and ege_g (dx2y2,dz2d_{x^2-y^2}, d_{z^2}) of higher energy.

The energy difference between the two sets of split dd-orbitals is denoted as Δo\Delta_o (Octahedral Crystal Field Splitting Energy).

Spectrochemical Series: Ligands are arranged in order of increasing field strength: I<Br<SCN<Cl<S2<F<OH<C2O42<H2O<NCS<edta4<NH3<en<CN<COI^- < Br^- < SCN^- < Cl^- < S^{2-} < F^- < OH^- < C_2O_4^{2-} < H_2O < NCS^- < edta^{4-} < NH_3 < en < CN^- < CO.

In Tetrahedral complexes, the splitting is inverted: ee orbitals (dx2y2,dz2d_{x^2-y^2}, d_{z^2}) have lower energy than t2t_2 orbitals (dxy,dyz,dzxd_{xy}, d_{yz}, d_{zx}). The splitting energy is Δt\Delta_t.

Strong field ligands result in Δo>P\Delta_o > P (Pairing energy), favoring low-spin complexes (pairing occurs). Weak field ligands result in Δo<P\Delta_o < P, favoring high-spin complexes.

The color of coordination compounds arises from ddd-d transitions, where an electron absorbs light to move from a lower energy dd-orbital to a higher energy dd-orbital.

📐Formulae

CFSEoct=[0.4n(t2g)+0.6n(eg)]Δo+nPCFSE_{oct} = [-0.4n(t_{2g}) + 0.6n(e_g)]\Delta_o + nP

Δt=49Δo\Delta_t = \frac{4}{9}\Delta_o

μeff=n(n+2) B.M.\mu_{eff} = \sqrt{n(n+2)} \text{ B.M.}

CFSEtet=[0.6n(e)+0.4n(t2)]ΔtCFSE_{tet} = [-0.6n(e) + 0.4n(t_2)]\Delta_t

💡Examples

Problem 1:

Calculate the Crystal Field Stabilization Energy (CFSE) for a d6d^6 ion in an octahedral field for both strong field and weak field ligand environments.

Solution:

  1. For Weak Field (High Spin): Configuration is t2g4eg2t_{2g}^4 e_g^2. CFSE=[4×(0.4)+2×(0.6)]Δo=0.4ΔoCFSE = [4 \times (-0.4) + 2 \times (0.6)]\Delta_o = -0.4\Delta_o.
  2. For Strong Field (Low Spin): Configuration is t2g6eg0t_{2g}^6 e_g^0. CFSE=[6×(0.4)+0×(0.6)]Δo+3P=2.4Δo+3PCFSE = [6 \times (-0.4) + 0 \times (0.6)]\Delta_o + 3P = -2.4\Delta_o + 3P.

Explanation:

In weak fields, Δo\Delta_o is small, so electrons occupy ege_g before pairing. In strong fields, Δo\Delta_o is large, so electrons pair up in the t2gt_{2g} level first.

Problem 2:

Explain why [Ti(H2O)6]3+[Ti(H_2O)_6]^{3+} is violet in color.

Solution:

In [Ti(H2O)6]3+[Ti(H_2O)_6]^{3+}, the Ti3+Ti^{3+} ion has a d1d^1 configuration (t2g1eg0t_{2g}^1 e_g^0). When white light falls on the complex, the single electron absorbs energy in the green-yellow region to jump to the ege_g level (ddd-d transition).

Explanation:

The absorption of specific wavelengths of light results in the transmission of the complementary color, which in this case is violet.

Crystal Field Theory (CFT) - Revision Notes & Key Formulas | ICSE Class 12 Chemistry