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Structure 3. Classification of matter - Functional groups: Classification of organic compounds

Grade 12IBChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A homologous series is a series of compounds that can be described by the same general formula, such as CnH2n+2C_nH_{2n+2} for alkanes. Members have similar chemical properties and show a gradation in physical properties like boiling point.

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Functional groups are specific atoms or groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules.

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Saturated compounds contain only single bonds between carbon atoms (e.g., alkanes), while unsaturated compounds contain double (alkenes, C=CC=C) or triple (alkynes, C≡CC\equiv C) carbon-carbon bonds.

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Alcohols are characterized by the hydroxyl group (−OH-OH). They are classified as primary (1∘1^{\circ}), secondary (2∘2^{\circ}), or tertiary (3∘3^{\circ}) based on the number of carbon atoms attached to the carbon bearing the −OH-OH group.

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Carbonyl groups (C=OC=O) are found in both aldehydes and ketones. In aldehydes, the carbonyl group is at the end of the carbon chain (−CHO-CHO), while in ketones, it is within the chain (−CO−-CO-).

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Carboxylic acids contain the carboxyl group (−COOH-COOH), which consists of a carbonyl group and a hydroxyl group attached to the same carbon atom.

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Esters are derived from carboxylic acids where the hydrogen of the −OH-OH group is replaced by an alkyl group (−COOR-COOR). They are often responsible for fruity smells.

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Amines contain the amino group (−NH2,−NHR, or −NR2-NH_2, -NHR, \text{ or } -NR_2), and amides contain a carbonyl group linked to a nitrogen atom (−CONH2-CONH_2).

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Arenes (aromatic hydrocarbons) contain a benzene ring (C6H6C_6H_6), which consists of a hexagonal ring of carbon atoms with delocalized π\pi electrons.

📐Formulae

CnH2n+2 (Alkanes)C_nH_{2n+2} \text{ (Alkanes)}

CnH2n (Alkenes)C_nH_{2n} \text{ (Alkenes)}

CnH2n−2 (Alkynes)C_nH_{2n-2} \text{ (Alkynes)}

CnH2n+1OH (Alcohols)C_nH_{2n+1}OH \text{ (Alcohols)}

CnH2n+1CHO (Aldehydes)C_nH_{2n+1}CHO \text{ (Aldehydes)}

CnH2nO (Ketones/Aldehydes isomerism)C_nH_{2n}O \text{ (Ketones/Aldehydes isomerism)}

R−COOH (Carboxylic Acids)R-COOH \text{ (Carboxylic Acids)}

R−COOR′ (Esters)R-COOR' \text{ (Esters)}

💡Examples

Problem 1:

Identify the functional group and the class of organic compound for the molecule CH3CH2COCH3CH_3CH_2COCH_3.

Solution:

Functional group: Carbonyl group (−CO−-CO-). Class: Ketone.

Explanation:

The molecule has a C=OC=O group bonded to two other carbon atoms within the chain, which defines it as a ketone (specifically, butanone).

Problem 2:

Classify the following alcohol as primary, secondary, or tertiary: CH3C(CH3)2OHCH_3C(CH_3)_2OH.

Solution:

Tertiary (3∘3^{\circ}) alcohol.

Explanation:

The carbon atom bonded to the hydroxyl group (−OH-OH) is attached to three other carbon atoms (three methyl groups), making it a tertiary alcohol (2-methylpropan-2-ol).

Problem 3:

Explain why the boiling point of CH3CH2CH2OHCH_3CH_2CH_2OH is significantly higher than that of CH3OCH2CH3CH_3OCH_2CH_3, even though they have the same molecular formula (C3H8OC_3H_8O).

Solution:

Propan-1-ol contains a hydroxyl group (−OH-OH) which allows for strong intermolecular hydrogen bonding, whereas ethoxymethane (an ether) only experiences weaker dipole-dipole and London dispersion forces.

Explanation:

Functional groups determine physical properties; the presence of −OH-OH in alcohols leads to hydrogen bonding, requiring more energy to overcome during boiling compared to the forces in ethers.