Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Metabolism involves the complex network of chemical reactions in cells, categorized into anabolism (building molecules, requiring energy, ) and catabolism (breaking down molecules, releasing energy, ).
Amino acids are the building blocks of proteins and possess both an amino group () and a carboxyl group (). At specific , they exist as zwitterions: .
The isoelectric point () is the at which an amino acid has a net charge of zero. At , the amino acid is protonated and carries a positive charge; at , it is deprotonated and carries a negative charge.
Proteins have four levels of structure: Primary (sequence of amino acids), Secondary (-helices and -pleated sheets held by -bonds), Tertiary (3D folding due to -group interactions), and Quaternary (assembly of multiple polypeptide chains).
Enzymes function as biological catalysts by lowering the activation energy (). Enzyme kinetics are often described by the Michaelis-Menten model, where represents the substrate concentration at which the reaction rate is .
Lipids include triglycerides, which are esters formed from glycerol and three fatty acids. The degree of unsaturation in a lipid can be determined using the Iodine Number, defined as the mass of in grams that reacts with of the lipid.
Carbohydrates have the general empirical formula . Monosaccharides like glucose () undergo condensation reactions to form disaccharides and polysaccharides, linked by glycosidic bonds.
Vitamins are micronutrients. Fat-soluble vitamins (e.g., Vitamin ) have long hydrocarbon chains or rings, while water-soluble vitamins (e.g., Vitamin ) have multiple groups allowing for hydrogen bonding with water.
📐Formulae
💡Examples
Problem 1:
A sample of linoleic acid (, ) contains two double bonds. Calculate the Iodine Number of linoleic acid.
Solution:
- One mole of linoleic acid reacts with of because there are two double bonds.
- Mass of of linoleic acid = .
- Mass of of .
- Iodine Number = .
Explanation:
The Iodine Number measures the degree of unsaturation. Since each bond reacts with one molecule of via an addition reaction, the stoichiometry is for linoleic acid to .
Problem 2:
Explain the effect of a competitive inhibitor on the Michaelis-Menten constants and .
Solution:
remains unchanged; increases.
Explanation:
A competitive inhibitor competes with the substrate for the active site. At very high substrate concentrations (), the substrate outcompetes the inhibitor, so the maximum velocity () can still be reached. However, more substrate is needed to reach , thus the Michaelis constant () increases, indicating a lower affinity of the enzyme for the substrate in the presence of the inhibitor.
Problem 3:
Determine the dominant species of Glycine (, ) in a solution at .
Solution:
Explanation:
At , which is below the first (), both the amino group and the carboxyl group are fully protonated. The amino group exists as and the carboxyl group remains as , resulting in a net positive charge on the molecule.