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d-and f-Block Elements - Position in the Periodic Table

Grade 12CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The dd-block elements are found in Groups 3 to 12 of the periodic table, occupying the central part between the ss-block and pp-block elements.

A transition element is defined as one which has incompletely filled dd-orbitals in its ground state or in any one of its common oxidation states.

The dd-block consists of four series: 3d3d series (ScSc to ZnZn), 4d4d series (YY to CdCd), 5d5d series (LaLa, HfHf to HgHg), and 6d6d series (which is incomplete).

Zn,Cd,Zn, Cd, and HgHg of group 12 have full d10d^{10} configuration in their ground state as well as in their common oxidation states and are therefore not regarded as transition metals.

The ff-block elements, also known as inner transition elements, consist of two series: Lanthanoids (filling of 4f4f orbitals) and Actinoids (filling of 5f5f orbitals), placed separately at the bottom of the periodic table.

The transition elements are so named because their properties represent a transition between the highly electropositive ss-block elements and the highly electronegative pp-block elements.

📐Formulae

General electronic configuration of d-block elements: (n1)d110ns12\text{General electronic configuration of } d\text{-block elements: } (n-1)d^{1-10} ns^{1-2}

General electronic configuration of f-block elements: (n2)f114(n1)d01ns2\text{General electronic configuration of } f\text{-block elements: } (n-2)f^{1-14} (n-1)d^{0-1} ns^2

Electronic configuration of Chromium (Cr, Z=24): [Ar]3d54s1\text{Electronic configuration of Chromium (Cr, Z=24): } [Ar] 3d^5 4s^1

Electronic configuration of Copper (Cu, Z=29): [Ar]3d104s1\text{Electronic configuration of Copper (Cu, Z=29): } [Ar] 3d^{10} 4s^1

💡Examples

Problem 1:

On what basis can you say that Scandium (Z=21Z = 21) is a transition element but Zinc (Z=30Z = 30) is not?

Solution:

Scandium (Z=21Z = 21) has the ground state electronic configuration [Ar]3d14s2[Ar] 3d^1 4s^2. Since it has an incompletely filled 3d3d orbital, it is a transition element. Zinc (Z=30Z = 30) has the configuration [Ar]3d104s2[Ar] 3d^{10} 4s^2 in its ground state and [Ar]3d10[Ar] 3d^{10} in its +2+2 oxidation state. Since the dd-orbitals are completely filled in both cases, it is not a transition element.

Explanation:

The definition of a transition element requires an incomplete dd-subshell in either the atomic or a common ionic state.

Problem 2:

Silver atom has completely filled dd orbitals (4d104d^{10}) in its ground state. How can you say it is a transition element?

Solution:

Silver (Z=47Z = 47) has the ground state configuration [Kr]4d105s1[Kr] 4d^{10} 5s^1. However, in its common oxidation state +2+2 (Ag2+Ag^{2+}), the configuration becomes [Kr]4d9[Kr] 4d^9.

Explanation:

Because the dd-orbital is incompletely filled in the +2+2 oxidation state, Silver satisfies the definition of a transition element.

Problem 3:

Write the general electronic configuration of Lanthanoids.

Solution:

[Xe]4f1145d016s2[Xe] 4f^{1-14} 5d^{0-1} 6s^2

Explanation:

Lanthanoids involve the filling of the 4f4f subshell. The 5d5d orbital may contain 00 or 11 electron depending on the stability provided by exchange energy (e.g., Gadolinium).

Position in the Periodic Table - Revision Notes & Key Formulas | CBSE Class 12 Chemistry