Review the key concepts, formulae, and examples before starting your quiz.
πConcepts
Aldehydes and ketones undergo nucleophilic addition reactions because the carbonyl carbon is electrophilic due to the polar nature of the bond.
Aldehydes are generally more reactive than ketones in nucleophilic addition reactions due to steric factors and the effect of two alkyl groups in ketones which reduces the electrophilicity of the carbonyl carbon.
The boiling points of aldehydes and ketones are higher than non-polar compounds (ethers, hydrocarbons) but lower than alcohols and carboxylic acids because they cannot form intermolecular hydrogen bonds with themselves.
Carboxylic acids have higher boiling points than alcohols of similar molecular mass because they form stable cyclic dimers through extensive intermolecular hydrogen bonding.
Aldehydes reduce Tollens' reagent to form a silver mirror () and Fehling's solution to form a red precipitate of , whereas ketones do not.
Aldehydes and ketones with at least one -hydrogen undergo Aldol condensation in the presence of dilute alkali to form -hydroxy aldehydes (aldols) or -hydroxy ketones (ketols).
Aldehydes which do not have an -hydrogen atom (e.g., , ) undergo Cannizzaro reaction (self-oxidation and reduction) when treated with concentrated alkali.
The acidity of carboxylic acids is enhanced by electron-withdrawing groups (EWG) like , , and through the effect, which stabilizes the carboxylate ion ().
Hell-Volhard-Zelinsky (HVZ) reaction: Carboxylic acids having an -hydrogen are halogenated at the -position on treatment with or in the presence of small amount of red phosphorus.
πFormulae
π‘Examples
Problem 1:
Arrange the following compounds in increasing order of their reactivity towards nucleophilic addition: , , , .
Solution:
Explanation:
Reactivity decreases as the size and number of alkyl groups increase due to steric hindrance and the inductive effect (), which reduces the positive charge density on the carbonyl carbon.
Problem 2:
Identify the product formed when Propan-2-one reacts with .
Solution:
Acetone cyanohydrin (-Hydroxy--methylpropanenitrile)
Explanation:
The cyanide ion () acts as a nucleophile and attacks the carbonyl carbon of , followed by protonation of the oxygen to form .
Problem 3:
Which is a stronger acid: or ?
Solution:
(Chloroacetic acid) is stronger.
Explanation:
The chlorine atom is an electron-withdrawing group ( effect). It withdraws electron density from the carboxylate group, stabilizing the ion more effectively than the effect of the methyl group in acetic acid stabilizes .