Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Nature of Carbonyl Group: The carbonyl carbon is hybridized and forms three bonds. The fourth valence electron remains in a -orbital, forming a bond with oxygen. Due to the high electronegativity of oxygen, the bond is highly polar: .
Mechanism of Nucleophilic Addition: A nucleophile () attacks the electrophilic carbonyl carbon from a direction perpendicular to the plane of hybridized orbitals. Hybridization changes from to , forming a tetrahedral intermediate which then captures a proton () to give the final product.
Reactivity Trends: Aldehydes are generally more reactive than ketones towards nucleophilic addition due to: (1) Steric factors: Two relatively large substituents in ketones hinder the approach of the nucleophile. (2) Inductive effect: Two electron-releasing alkyl groups in ketones reduce the electrophilicity of the carbonyl carbon.
Addition of : Aldehydes and ketones react with hydrogen cyanide to yield cyanohydrins. The reaction is slow with pure and is catalyzed by a base to generate the stronger nucleophile .
Addition of Alcohols: Aldehydes react with one equivalent of monohydric alcohol in the presence of dry gas to form hemiacetals, and with another equivalent to form acetals. Ketones react with ethylene glycol to form cyclic ketals.
Addition of Ammonia Derivatives: Nucleophiles such as and its derivatives () add to the carbonyl group. The reaction is followed by the elimination of a water molecule to form compounds containing the linkage.
📐Formulae
💡Examples
Problem 1:
Arrange the following compounds in increasing order of their reactivity in nucleophilic addition reactions: Ethanal (), Propanal (), Propanone (), Butanone ().
Solution:
Butanone < Propanone < Propanal < Ethanal
Explanation:
Reactivity decreases as the size and number of alkyl groups attached to the carbonyl carbon increase. Ketones (Butanone, Propanone) are less reactive than aldehydes (Propanal, Ethanal) due to both steric hindrance and the effect of two alkyl groups reducing the positive charge on the carbon. Ethanal is more reactive than propanal because the methyl group is smaller and has a weaker effect than the ethyl group.
Problem 2:
Predict the product formed when Cyclohexanone reacts with Semicarbazide () in a weakly acidic medium.
Solution:
Cyclohexanone semicarbazone:
Explanation:
This is a nucleophilic addition-elimination reaction. The group of the semicarbazide (which is not attached to the carbonyl group) acts as a nucleophile. It attacks the carbonyl carbon of cyclohexanone, followed by the loss of a water molecule () to form a bond.
Problem 3:
Why is the addition of to a carbonyl compound carried out in the presence of a base?
Solution:
To generate the nucleophile .
Explanation:
Hydrogen cyanide () is a weak acid and a poor nucleophile. In the presence of a base (), it undergoes deprotonation: . The cyanide ion () is a much stronger nucleophile and readily attacks the electrophilic carbonyl carbon.