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The Periodic Table - Transition elements

Grade 11IGCSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Transition elements are the collection of metallic elements located in the center of the Periodic Table, specifically in the d-block between Groups 2 and 13.

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Physical properties include high density, high melting points, and being hard and strong compared to Group 1 and 2 metals.

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Chemical properties distinct to transition metals include variable oxidation states (e.g., Fe2+Fe^{2+} and Fe3+Fe^{3+}), the formation of colored compounds, and acting as catalysts.

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Transition metals form colored ions in solution. For example, Cu2+Cu^{2+} ions typically appear blue, while Cr3+Cr^{3+} ions appear green.

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Catalytic activity is a key industrial application. For instance, Iron (FeFe) is used in the Haber process to synthesize NH3NH_3, and Vanadium(V) oxide (V2O5V_2O_5) is used in the Contact process.

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Unlike Group 1 metals, transition metals are relatively unreactive with water and oxygen at room temperature, making them useful construction materials.

πŸ“Formulae

N2(g)+3H2(g)β†’Fe2NH3(g)N_2(g) + 3H_2(g) \xrightarrow{Fe} 2NH_3(g)

2SO2(g)+O2(g)β†’V2O52SO3(g)2SO_2(g) + O_2(g) \xrightarrow{V_2O_5} 2SO_3(g)

Fe2+(aq)+2OHβˆ’(aq)β†’Fe(OH)2(s)Fe^{2+}(aq) + 2OH^-(aq) \rightarrow Fe(OH)_2(s)

Cu2+(aq)+2OHβˆ’(aq)β†’Cu(OH)2(s)Cu^{2+}(aq) + 2OH^-(aq) \rightarrow Cu(OH)_2(s)

πŸ’‘Examples

Problem 1:

Identify which of the following elements is a transition metal based on its properties: Sodium (NaNa), Iron (FeFe), or Calcium (CaCa). Provide two reasons for your choice.

Solution:

Iron (FeFe) is the transition metal.

Explanation:

Sodium (NaNa) is an alkali metal and Calcium (CaCa) is an alkaline earth metal. Iron (FeFe) is a transition metal because it can form ions with different charges such as Fe2+Fe^{2+} and Fe3+Fe^{3+}, and it acts as a catalyst in industrial reactions like the Haber process.

Problem 2:

A student adds sodium hydroxide solution, NaOH(aq)NaOH(aq), to an unknown solution containing transition metal ions. A blue precipitate forms. Identify the ion present and write the ionic equation for the reaction.

Solution:

The ion present is Cu2+Cu^{2+}. The ionic equation is: Cu2+(aq)+2OHβˆ’(aq)β†’Cu(OH)2(s)Cu^{2+}(aq) + 2OH^-(aq) \rightarrow Cu(OH)_2(s)

Explanation:

Transition metal ions produce characteristic colored precipitates with hydroxide ions. A blue precipitate specifically indicates the presence of Copper(II) ions, forming Copper(II) hydroxide.

Transition elements - Revision Notes & Key Formulas | IGCSE Grade 11 Chemistry