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The Periodic Table - Group 8/0: Noble gases

Grade 11IGCSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Group 8 (also known as Group 0) elements are the noble gases: Helium (HeHe), Neon (NeNe), Argon (ArAr), Krypton (KrKr), Xenon (XeXe), and Radon (RnRn).

They possess a full outer shell of electrons (ns2np6ns^2 np^6, except Helium which is 1s21s^2), making them exceptionally stable and chemically inert.

Noble gases are monatomic, meaning they exist as single atoms rather than molecules (e.g., ArAr instead of Ar2Ar_2).

Physical Trends: As you move down the group, the boiling points and densities increase due to the increase in the number of electrons and stronger interatomic forces (London dispersion forces).

Chemical Properties: They do not easily form compounds because they do not need to lose, gain, or share electrons to achieve stability.

Common uses include: Helium (HeHe) for balloons and airships due to low density; Neon (NeNe) for advertising signs; and Argon (ArAr) to provide an inert atmosphere in light bulbs and welding.

📐Formulae

Helium: 1s2 (2 valence electrons)\text{Helium: } 1s^2 \text{ (2 valence electrons)}

Neon: 1s22s22p6 (8 valence electrons)\text{Neon: } 1s^2 2s^2 2p^6 \text{ (8 valence electrons)}

Argon: 1s22s22p63s23p6 (8 valence electrons)\text{Argon: } 1s^2 2s^2 2p^6 3s^2 3p^6 \text{ (8 valence electrons)}

Density Trend: ρHe<ρNe<ρAr<ρKr\text{Density Trend: } \rho_{He} < \rho_{Ne} < \rho_{Ar} < \rho_{Kr}

💡Examples

Problem 1:

Explain why the boiling point of Xenon (XeXe) is higher than the boiling point of Neon (NeNe).

Solution:

BPXe>BPNeBP_{Xe} > BP_{Ne}

Explanation:

As you move down Group 0, the size of the atoms increases and the total number of electrons increases. This leads to stronger temporary dipoles and stronger intermolecular (interatomic) forces, requiring more thermal energy to overcome, thus increasing the boiling point.

Problem 2:

Predict the chemical reactivity of Argon (ArAr) when mixed with Oxygen (O2O_2) at high temperatures.

Solution:

Ar(g)+O2(g)No ReactionAr(g) + O_2(g) \rightarrow \text{No Reaction}

Explanation:

Argon has a complete octet of 88 electrons in its outer shell. This electronic configuration is extremely stable, so Argon has no tendency to react with Oxygen or other elements under standard conditions.

Problem 3:

State one use of Argon (ArAr) and the property that makes it suitable for this use.

Solution:

Used in incandescent light bulbs.

Explanation:

Argon provides an inert atmosphere that prevents the hot tungsten (WW) filament from oxidizing (reacting with oxygen), which would cause the filament to burn out quickly.

Group 8/0: Noble gases - Revision Notes & Key Formulas | IGCSE Grade 11 Chemistry