Structure 3. Classification of matter - Functional groups: Classification of organic compounds
Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
A homologous series is a series of compounds that can be described by the same general formula, such as for alkanes. Members have similar chemical properties and show a gradation in physical properties like boiling point.
Functional groups are specific atoms or groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules.
Saturated compounds contain only single bonds between carbon atoms (e.g., alkanes), while unsaturated compounds contain double (alkenes, ) or triple (alkynes, ) carbon-carbon bonds.
Alcohols are characterized by the hydroxyl group (). They are classified as primary (), secondary (), or tertiary () based on the number of carbon atoms attached to the carbon bearing the group.
Carbonyl groups () are found in both aldehydes and ketones. In aldehydes, the carbonyl group is at the end of the carbon chain (), while in ketones, it is within the chain ().
Carboxylic acids contain the carboxyl group (), which consists of a carbonyl group and a hydroxyl group attached to the same carbon atom.
Esters are derived from carboxylic acids where the hydrogen of the group is replaced by an alkyl group (). They are often responsible for fruity smells.
Amines contain the amino group (), and amides contain a carbonyl group linked to a nitrogen atom ().
Arenes (aromatic hydrocarbons) contain a benzene ring (), which consists of a hexagonal ring of carbon atoms with delocalized electrons.
📐Formulae
💡Examples
Problem 1:
Identify the functional group and the class of organic compound for the molecule .
Solution:
Functional group: Carbonyl group (). Class: Ketone.
Explanation:
The molecule has a group bonded to two other carbon atoms within the chain, which defines it as a ketone (specifically, butanone).
Problem 2:
Classify the following alcohol as primary, secondary, or tertiary: .
Solution:
Tertiary () alcohol.
Explanation:
The carbon atom bonded to the hydroxyl group () is attached to three other carbon atoms (three methyl groups), making it a tertiary alcohol (2-methylpropan-2-ol).
Problem 3:
Explain why the boiling point of is significantly higher than that of , even though they have the same molecular formula ().
Solution:
Propan-1-ol contains a hydroxyl group () which allows for strong intermolecular hydrogen bonding, whereas ethoxymethane (an ether) only experiences weaker dipole-dipole and London dispersion forces.
Explanation:
Functional groups determine physical properties; the presence of in alcohols leads to hydrogen bonding, requiring more energy to overcome during boiling compared to the forces in ethers.