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Chemical Bonding and Structure - Metallic bonding

Grade 11IBChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Metallic bonding is the electrostatic attraction between a lattice of positive metal ions (Mn+M^{n+}) and a 'sea' of delocalized valence electrons.

The strength of the metallic bond depends on the charge density of the metal ions. It increases with an increase in the number of valence electrons (charge qq) and a decrease in the ionic radius (rr).

Metals are excellent electrical conductors because the delocalized electrons are free to move throughout the lattice when a potential difference is applied.

Thermal conductivity in metals is high because both the delocalized electrons and the vibrations of the closely packed ions facilitate the transfer of kinetic energy.

Malleability and ductility arise because the metallic bond is non-directional; layers of ions can slide over each other without breaking the bond, as the 'sea' of electrons acts as a flexible glue.

Alloys are solid solutions or mixtures of a metal with other elements (metals or non-metals, such as Carbon in Steel). Alloys are usually harder than pure metals because atoms of different sizes disrupt the regular lattice structure, preventing layers from sliding easily.

📐Formulae

Strength of bondCharge of ionIonic radius\text{Strength of bond} \propto \frac{\text{Charge of ion}}{\text{Ionic radius}}

F=kq1q2r2F = k \frac{q_1 q_2}{r^2}

Charge Density=neV\text{Charge Density} = \frac{n e}{V}

💡Examples

Problem 1:

Explain why Aluminum (AlAl) has a higher melting point than Sodium (NaNa).

Solution:

AlAl has a melting point of approximately 933 K933\text{ K}, while NaNa has a melting point of approximately 371 K371\text{ K}.

Explanation:

Aluminum forms Al3+Al^{3+} ions and contributes three delocalized electrons per atom to the 'sea', whereas Sodium forms Na+Na^+ ions and contributes only one. The Al3+Al^{3+} ion has a higher charge and a smaller ionic radius than Na+Na^+, resulting in a much higher charge density. This leads to a stronger electrostatic attraction between the Al3+Al^{3+} cations and the delocalized electrons, requiring more energy to break the lattice.

Problem 2:

Why is Brass (an alloy of CuCu and ZnZn) harder than pure Copper (CuCu)?

Solution:

The addition of ZnZn atoms into the CuCu lattice creates irregularities.

Explanation:

In pure CuCu, the atoms are of uniform size and arranged in regular layers that can easily slide over one another when force is applied. In Brass, the ZnZn atoms have a different atomic radius than CuCu. These differently sized atoms distort the regular lattice layers, making it significantly more difficult for the layers to slide over each other, thus increasing the hardness of the material.

Metallic bonding - Revision Notes & Key Formulas | IB Grade 11 Chemistry