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Chemical Bonding and Structure - Intermolecular forces

Grade 11IBChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Intermolecular forces (IMFs) are the forces of attraction between molecules, which determine physical properties like boiling point, melting point, and solubility. They are much weaker than intramolecular forces (covalent, ionic, or metallic bonds).

London (Dispersion) Forces: The weakest IMF, present in all molecules. They arise from temporary dipoles caused by the movement of electrons, which induce dipoles in neighboring molecules. Their strength increases with the number of electrons (molar mass) and surface area (e.g.,e.g., C5H12C_5H_{12} has higher LDFs than CH4CH_4).

Dipole-Dipole Attraction: Occurs between polar molecules that have permanent dipoles. The positive end of one polar molecule is attracted to the negative end of another (e.g.,e.g., in HClHCl or CH3ClCH_3Cl).

Hydrogen Bonding: A particularly strong type of dipole-dipole attraction that occurs when hydrogen is covalently bonded to a highly electronegative atom: Nitrogen (NN), Oxygen (OO), or Fluorine (FF). Examples include H2OH_2O, NH3NH_3, and HFHF.

Physical Properties: Substances with stronger IMFs have higher boiling and melting points because more energy is required to overcome these attractions. For example, H2OH_2O has a much higher boiling point than H2SH_2S due to hydrogen bonding.

Solubility: 'Like dissolves like.' Polar solutes (and many ionic compounds) tend to dissolve in polar solvents like H2OH_2O. Non-polar solutes (like I2I_2) dissolve in non-polar solvents (like C6H14C_6H_{14}).

📐Formulae

Δχ=χAχB\Delta \chi = |\chi_A - \chi_B|

μ=q×d\mu = q \times d

VLondonα1α2r6V_{London} \propto -\frac{\alpha_1 \alpha_2}{r^6}

💡Examples

Problem 1:

Explain why the boiling point of HFHF (293K293\,K) is significantly higher than that of HClHCl (188K188\,K), even though HClHCl has more electrons.

Solution:

HFHF exhibits hydrogen bonding, whereas HClHCl only exhibits dipole-dipole forces and London dispersion forces.

Explanation:

In HFHF, the hydrogen is bonded to fluorine, the most electronegative element. This creates a highly polar bond and allows for hydrogen bonding, the strongest type of intermolecular force. Despite HClHCl having a larger electron cloud (leading to stronger London dispersion forces), the strength of the hydrogen bonds in HFHF requires much more thermal energy to overcome, resulting in a higher boiling point.

Problem 2:

Predict and justify the order of increasing boiling points for the following: CH4CH_4, C2H6C_2H_6, CH3OHCH_3OH.

Solution:

CH4<C2H6<CH3OHCH_4 < C_2H_6 < CH_3OH

Explanation:

CH4CH_4 and C2H6C_2H_6 are both non-polar molecules that only experience London dispersion forces. C2H6C_2H_6 has a higher boiling point than CH4CH_4 because it has more electrons and a larger surface area, leading to stronger dispersion forces. CH3OHCH_3OH (methanol) has the highest boiling point because it contains an OH-OH group, which allows the molecules to form strong hydrogen bonds.

Intermolecular forces - Revision Notes & Key Formulas | IB Grade 11 Chemistry