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Reproduction - Asexual and sexual reproduction

Grade 12A LevelBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Asexual reproduction is the process resulting in the production of genetically identical offspring from one parent, without the fusion of gametes or change in chromosome number (2n→2n2n \rightarrow 2n).

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Sexual reproduction involves the fusion of two haploid (nn) gamete nuclei to form a diploid (2n2n) zygote, resulting in genetically diverse offspring.

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The cellular mechanism for asexual reproduction is mitosis, whereas sexual reproduction relies on meiosis to produce haploid gametes (nn) from diploid germ cells (2n2n).

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Genetic variation in sexual reproduction is driven by three main factors: crossing over during Prophase I, independent assortment during Metaphase I, and random fertilization of gametes.

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Advantages of asexual reproduction include rapid population growth and no requirement for a mate, while sexual reproduction allows for adaptation to changing environments through genetic diversity.

📐Formulae

n+n→2nn + n \rightarrow 2n

2n2^n

Variation Index∝Rate of Meiotic Recombination\text{Variation Index} \propto \text{Rate of Meiotic Recombination}

💡Examples

Problem 1:

In a species of lily, the diploid chromosome number is 2n=242n = 24. If a pollen grain (male gamete) fertilizes an egg cell, calculate the chromosome number of the resulting zygote and the number of chromosomes in a leaf cell produced by asexual vegetative propagation.

Solution:

Zygote chromosome number = 2424; Leaf cell chromosome number = 2424.

Explanation:

The pollen and egg are haploid (n=12n = 12). Their fusion restores the diploid state (n+n=12+12=24n + n = 12 + 12 = 24). A leaf cell produced via asexual propagation is formed through mitosis, which maintains the original diploid number (2n=242n = 24).

Problem 2:

Calculate the total number of possible genetic combinations in the gametes of an organism where 2n=82n = 8, assuming variation is only due to independent assortment.

Solution:

24=162^4 = 16 combinations.

Explanation:

The number of possible combinations due to independent assortment is calculated using the formula 2n2^n, where nn is the haploid number. Since 2n=82n = 8, n=4n = 4. Therefore, 24=162^4 = 16.