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Movement in and out of Cells - Osmosis

Grade 12IGCSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Osmosis is defined as the net movement of water molecules from a region of higher water potential (dilute solution) to a region of lower water potential (concentrated solution), through a partially permeable membrane.

Water potential (Psi\\Psi) is a measure of the tendency of water molecules to move from one area to another. Pure water has the highest potential, defined as 0 kPa0\text{ kPa}. All solutions have a negative water potential.

In plant cells, water entering via osmosis creates turgor pressure. This pressure pushes the cell membrane against the rigid cell wall, making the cell 'turgid', which provides structural support to the plant.

When plant cells lose water, they become 'flaccid'. If water loss continues, the cell membrane pulls away from the cell wall, a process known as plasmolysis.

Animal cells lack a cell wall. In a hypotonic solution (high water potential), water enters the cell until it bursts, a process called lysis. In a hypertonic solution (low water potential), the cell loses water and shrivels, known as crenation.

A partially permeable membrane (e.g., the cell membrane) allows small molecules like H2OH_2O to pass through but prevents larger solute molecules like glucose or sucrose from crossing easily.

📐Formulae

Percentage Change in Mass=Final MassInitial MassInitial Mass×100\text{Percentage Change in Mass} = \frac{\text{Final Mass} - \text{Initial Mass}}{\text{Initial Mass}} \times 100

Ψ=Ψs+Ψp\Psi = \Psi_s + \Psi_p

Rate of OsmosisSurface Area×Difference in ΨThickness of Membrane\text{Rate of Osmosis} \propto \frac{\text{Surface Area} \times \text{Difference in } \Psi}{\text{Thickness of Membrane}}

💡Examples

Problem 1:

A potato tissue strip with an initial mass of 5.00 g5.00\text{ g} is placed in a 1.0 mol/dm31.0\text{ mol/dm}^3 sugar solution. After 30 minutes, the mass of the strip is 4.25 g4.25\text{ g}. Calculate the percentage change in mass and explain the direction of water movement.

Solution:

Change=4.255.005.00×100=15%\text{Change} = \frac{4.25 - 5.00}{5.00} \times 100 = -15\%

Explanation:

The negative result (15%-15\%) indicates a loss in mass. This occurs because the sugar solution is hypertonic (has a lower water potential) relative to the potato cells. Consequently, water moved out of the potato cells by osmosis, across the partially permeable cell membranes.

Problem 2:

Explain what happens to a red blood cell when placed in a solution of 0%0\% salinity (pure H2OH_2O).

Solution:

The red blood cell will undergo hemolysis (burst).

Explanation:

Pure H2OH_2O has a water potential of 0 kPa0\text{ kPa}, which is higher than the water potential inside the red blood cell's cytoplasm. Water moves into the cell via osmosis down the water potential gradient. Since animal cells lack a cell wall to resist the internal pressure, the membrane eventually ruptures.

Osmosis - Revision Notes & Key Diagrams | IGCSE Grade 12 Biology