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Inheritance - Chromosomes, genes and proteins

Grade 12IGCSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Chromosomes are thread-like structures made of DNA and proteins, found in the nucleus. They carry genetic information in the form of genes. In humans, the diploid number is 2n=462n = 46 and the haploid number is n=23n = 23.

A gene is defined as a length of DNA that codes for a specific protein. Alleles are alternative forms of a gene that occupy the same locus on a chromosome.

DNA is a double helix consisting of two strands of nucleotides. Each nucleotide contains a phosphate group, a deoxyribose sugar, and a nitrogenous base: Adenine (AA), Thymine (TT), Cytosine (CC), or Guanine (GG).

DNA controls cell function by controlling the production of proteins (enzymes, antibodies, and receptors). The sequence of bases in a gene determines the sequence of amino acids used to build a specific protein.

Protein synthesis involves two stages: Transcription, where an mRNAmRNA molecule is made from the DNA template in the nucleus, and Translation, where the ribosome reads the mRNAmRNA codons to assemble amino acids into a polypeptide chain.

The genetic code is a triplet code. Each sequence of three bases, called a codon (e.g., AUGAUG, GCAGCA), specifies one amino acid.

📐Formulae

2n=Total number of chromosomes in a diploid cell2n = \text{Total number of chromosomes in a diploid cell}

n=Total number of chromosomes in a haploid cell (gamete)n = \text{Total number of chromosomes in a haploid cell (gamete)}

[A]=[T] and [C]=[G][A] = [T] \text{ and } [C] = [G]

Number of bases=3×Number of amino acids\text{Number of bases} = 3 \times \text{Number of amino acids}

💡Examples

Problem 1:

A specific protein consists of 150150 amino acids. Calculate the minimum number of nitrogenous bases in the gene that codes for this protein.

Solution:

150×3=450 bases150 \times 3 = 450 \text{ bases}

Explanation:

Since each amino acid is coded for by a triplet of bases (a codon), you multiply the number of amino acids by 33 to find the number of bases.

Problem 2:

If a double-stranded DNA molecule contains 22%22\% Cytosine (CC), calculate the percentage of Thymine (TT) in the molecule.

Solution:

  1. If C=22%C = 22\%, then G=22%G = 22\%.
  2. C+G=44%C + G = 44\%.
  3. A+T=100%44%=56%A + T = 100\% - 44\% = 56\%.
  4. T=56%2=28%T = \frac{56\%}{2} = 28\%.

Explanation:

According to complementary base pairing rules, the amount of Cytosine equals Guanine, and the amount of Adenine equals Thymine.

Problem 3:

Identify the mRNAmRNA sequence transcribed from the DNA template strand sequence: 3TACGGCAAT53'-TAC-GGC-AAT-5'.

Solution:

5AUGCCGUUA35'-AUG-CCG-UUA-3'

Explanation:

During transcription, AA pairs with UU (Uracil in mRNAmRNA), TT pairs with AA, CC pairs with GG, and GG pairs with CC. The strands are antiparallel.

Chromosomes, genes and proteins - Revision Notes & Key Diagrams | IGCSE Grade 12 Biology