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Genetics - Chromosomes

Grade 12IBBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Prokaryotic chromosomes consist of a single, circular DNA molecule that is not associated with proteins (often referred to as 'naked' DNA).

Some prokaryotes also contain plasmids, which are small, circular, extra-chromosomal DNA molecules that often carry genes for antibiotic resistance.

Eukaryotic chromosomes are linear DNA molecules associated with histone proteins. The DNA wraps around eight histones to form a nucleosome, which further coils into a 30 nm30\text{ nm} fiber.

Homologous chromosomes are pairs of chromosomes that have the same sequence of genes at the same loci, though they may carry different alleles (e.g., allele AA vs aa).

A diploid nucleus (2n2n) has two sets of chromosomes (one from each parent), whereas a haploid nucleus (nn) has only one set of chromosomes.

The number of chromosomes is a characteristic feature of a species; for example, humans have 2n=462n = 46 chromosomes (n=23n = 23).

Sex is determined by the 23rd23^{rd} pair of chromosomes in humans: XXXX results in a female, and XYXY results in a male. All other chromosomes are called autosomes.

A karyogram is an image of the chromosomes of an organism, arranged in homologous pairs of decreasing length. It is used to diagnose chromosomal abnormalities such as Trisomy 2121 (Down Syndrome).

📐Formulae

2n=Diploid number of chromosomes2n = \text{Diploid number of chromosomes}

n=Haploid number of chromosomesn = \text{Haploid number of chromosomes}

2n=Number of possible chromosome combinations in gametes (due to independent assortment)2^n = \text{Number of possible chromosome combinations in gametes (due to independent assortment)}

2n×2n=Number of possible zygotic combinations (excluding crossing over)2^n \times 2^n = \text{Number of possible zygotic combinations (excluding crossing over)}

💡Examples

Problem 1:

A cell from an organism with a diploid number of 2n=82n = 8 undergoes meiosis. Calculate the total number of possible chromosome combinations that can occur in the resulting gametes due to independent assortment.

Solution:

24=162^4 = 16

Explanation:

Since 2n=82n = 8, the haploid number is n=4n = 4. Using the formula 2n2^n for independent assortment, we calculate 242^4, which equals 1616 possible combinations.

Problem 2:

Identify the chromosomal abnormality and the sex of an individual whose karyogram shows three copies of chromosome 2121 and the sex chromosomes XX and YY.

Solution:

Condition: Trisomy 2121 (Down Syndrome); Sex: Male.

Explanation:

The presence of three chromosomes at position 2121 indicates Trisomy 2121. The presence of one XX and one YY chromosome indicates the individual is male (XYXY).

Problem 3:

In a human cell (n=23n = 23), how many DNA molecules are present during the G2G_2 phase of the cell cycle?

Solution:

9292 DNA molecules.

Explanation:

In humans, the diploid number is 2n=462n = 46. During the SS phase, DNA replication occurs, doubling the amount of DNA. Therefore, in G2G_2, there are 4646 chromosomes, each consisting of two sister chromatids, resulting in 46×2=9246 \times 2 = 92 DNA molecules.

Chromosomes - Revision Notes & Key Diagrams | IB Grade 12 Biology