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Continuity and change - Reproduction

Grade 12IBBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Asexual reproduction involves a single parent and produces offspring that are genetically identical to the parent (clones). This occurs through processes like binary fission, budding, or vegetative propagation.

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Sexual reproduction involves the fusion of two haploid (nn) gametes to form a diploid (2n2n) zygote, ensuring genetic variation within a population.

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Meiosis is a reduction division where the chromosome number is halved from diploid (2n2n) to haploid (nn). It introduces variation via crossing over in Prophase I and independent assortment in Metaphase I.

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Genetic variation in gametes can be calculated using the formula 2n2^n, where nn is the haploid number of chromosomes.

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Human reproduction is regulated by the endocrine system. The menstrual cycle involves hormones from the hypothalamus (GnRH), anterior pituitary (FSH and LH), and ovaries (Estrogen and Progesterone).

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Fertilization in humans typically occurs in the fallopian tube (oviduct). The resulting zygote undergoes mitosis to become a blastocyst before implanting in the endometrium.

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The placenta is a specialized organ that facilitates the exchange of nutrients, gases, and wastes between maternal and fetal blood without the two blood supplies mixing directly.

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External fertilization occurs outside the body (common in aquatic species like fish and amphibians), while internal fertilization occurs inside the female reproductive tract (common in terrestrial animals).

📐Formulae

n+n→2nn + n \rightarrow 2n

Number of possible chromosome combinations=2n\text{Number of possible chromosome combinations} = 2^n

Surface Area to Volume Ratio=SAV\text{Surface Area to Volume Ratio} = \frac{SA}{V}

💡Examples

Problem 1:

A species of plant has a diploid chromosome number of 2n=122n = 12. Calculate the number of possible chromosome combinations that can occur in its gametes as a result of independent assortment during meiosis.

Solution:

Given 2n=122n = 12, the haploid number nn is: n=122=6n = \frac{12}{2} = 6 The number of combinations is given by: 2n=26=642^n = 2^6 = 64

Explanation:

Independent assortment occurs during Metaphase I of meiosis, where homologous pairs align randomly. The total number of unique combinations of maternal and paternal chromosomes is 22 raised to the power of the haploid number.

Problem 2:

Explain the role of the hormone LHLH (Luteinizing Hormone) in the human menstrual cycle and identify its peak timing.

Solution:

The LHLH surge triggers ovulation (the release of the secondary oocyte). It occurs around day 1414 of a standard 2828-day cycle.

Explanation:

High levels of estrogen exert positive feedback on the pituitary gland, leading to a sudden spike in LHLH. This spike causes the Graafian follicle to rupture and subsequently transform into the corpus luteum.