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Sexual Reproduction in Flowering Plants - Pollination and Pollen-Pistil Interaction

Grade 12CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Pollination is the transfer of pollen grains from the anther to the stigma of a pistil. It is categorized into: Autogamy (same flower), Geitonogamy (different flower, same plant), and Xenogamy (different plant).

Abiotic agents of pollination include wind (AnemophilyAnemophily) and water (HydrophilyHydrophily). Wind-pollinated flowers have light, non-sticky pollen and well-exposed stamens, while water-pollinated plants like VallisneriaVallisneria and HydrillaHydrilla use water currents for transport.

Biotic agents (EntomophilyEntomophily, ZoophilyZoophily) involve insects, birds, or bats. Flowers are usually large, colorful, and fragrant, often providing nectar or pollen as rewards.

Outbreeding devices are mechanisms to discourage self-pollination and encourage cross-pollination to avoid inbreeding depression. Examples include dichogamy (different maturation times of anther and stigma) and self-incompatibility (genetic mechanism).

Pollen-Pistil Interaction is a dynamic process involving pollen recognition followed by promotion or inhibition of the pollen. It is mediated by chemical components of the pollen interacting with those of the pistil.

Pollen tube growth: If compatible, the pollen grain germinates on the stigma to produce a pollen tube through the germ pore. The tube grows through the tissues of the style and reaches the ovary, guided by the filiform apparatus of the synergids.

Double Fertilization: A unique event in angiosperms where one male gamete (nn) fuses with the egg (nn) to form a zygote (2n2n), and the second male gamete (nn) fuses with the two polar nuclei or secondary nucleus (2n2n) to form the Primary Endosperm Nucleus (3n3n).

📐Formulae

Syngamy: Egg (n)+Male Gamete (n)Zygote (2n)\text{Syngamy: } \text{Egg } (n) + \text{Male Gamete } (n) \rightarrow \text{Zygote } (2n)

Triple Fusion: Secondary Nucleus (2n)+Male Gamete (n)PEN (3n)\text{Triple Fusion: } \text{Secondary Nucleus } (2n) + \text{Male Gamete } (n) \rightarrow \text{PEN } (3n)

Total Meiotic Divisions for x seeds=x4 (for microspores)+x (for megaspores)=1.25x\text{Total Meiotic Divisions for } x \text{ seeds} = \frac{x}{4} \text{ (for microspores)} + x \text{ (for megaspores)} = 1.25x

💡Examples

Problem 1:

Calculate the total number of meiotic divisions required to produce 200200 seeds in a typical angiosperm plant.

Solution:

To produce 200200 seeds, we need 200200 pollen grains and 200200 functional megaspores.

  1. Number of meiotic divisions to produce 200200 pollen grains: Since 11 Microspore Mother Cell (MMC) produces 44 pollen grains via meiosis, we need 2004=50\frac{200}{4} = 50 divisions.
  2. Number of meiotic divisions to produce 200200 functional megaspores: Since 11 Megaspore Mother Cell (MMC) produces 44 megaspores but only 11 remains functional, we need 200200 divisions. Total divisions = 50+200=25050 + 200 = 250.

Explanation:

In angiosperms, microsporogenesis results in 4 functional grains per meiosis, whereas megasporogenesis results in only 1 functional megaspore per meiosis due to the degeneration of the other three.

Problem 2:

If the diploid number (2n2n) of a flowering plant is 2424, what will be the chromosome number in the cells of the nucellus, the pollen grain, and the endosperm?

Solution:

Given 2n=242n = 24, then n=12n = 12.

  1. Nucellus (sporophytic tissue): 2n=242n = 24.
  2. Pollen grain (gametophytic tissue): n=12n = 12.
  3. Endosperm (result of triple fusion): 3n=3×12=363n = 3 \times 12 = 36.

Explanation:

The nucellus is part of the ovule (diploid), the pollen grain is the male gametophyte (haploid), and the endosperm is formed by the fusion of three haploid nuclei (triploid).

Pollination and Pollen-Pistil Interaction Revision - Class 12 Biology CBSE