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Sexual Reproduction in Flowering Plants - Pollination and Pollen-Pistil Interaction

Grade 12CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Pollination is the transfer of pollen grains from the anther to the stigma of a pistil. It is categorized into: Autogamy (same flower), Geitonogamy (different flower, same plant), and Xenogamy (different plant).

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Abiotic agents of pollination include wind (AnemophilyAnemophily) and water (HydrophilyHydrophily). Wind-pollinated flowers have light, non-sticky pollen and well-exposed stamens, while water-pollinated plants like VallisneriaVallisneria and HydrillaHydrilla use water currents for transport.

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Biotic agents (EntomophilyEntomophily, ZoophilyZoophily) involve insects, birds, or bats. Flowers are usually large, colorful, and fragrant, often providing nectar or pollen as rewards.

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Outbreeding devices are mechanisms to discourage self-pollination and encourage cross-pollination to avoid inbreeding depression. Examples include dichogamy (different maturation times of anther and stigma) and self-incompatibility (genetic mechanism).

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Pollen-Pistil Interaction is a dynamic process involving pollen recognition followed by promotion or inhibition of the pollen. It is mediated by chemical components of the pollen interacting with those of the pistil.

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Pollen tube growth: If compatible, the pollen grain germinates on the stigma to produce a pollen tube through the germ pore. The tube grows through the tissues of the style and reaches the ovary, guided by the filiform apparatus of the synergids.

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Double Fertilization: A unique event in angiosperms where one male gamete (nn) fuses with the egg (nn) to form a zygote (2n2n), and the second male gamete (nn) fuses with the two polar nuclei or secondary nucleus (2n2n) to form the Primary Endosperm Nucleus (3n3n).

📐Formulae

Syngamy: Egg (n)+Male Gamete (n)→Zygote (2n)\text{Syngamy: } \text{Egg } (n) + \text{Male Gamete } (n) \rightarrow \text{Zygote } (2n)

Triple Fusion: Secondary Nucleus (2n)+Male Gamete (n)→PEN (3n)\text{Triple Fusion: } \text{Secondary Nucleus } (2n) + \text{Male Gamete } (n) \rightarrow \text{PEN } (3n)

Total Meiotic Divisions for x seeds=x4 (for microspores)+x (for megaspores)=1.25x\text{Total Meiotic Divisions for } x \text{ seeds} = \frac{x}{4} \text{ (for microspores)} + x \text{ (for megaspores)} = 1.25x

💡Examples

Problem 1:

Calculate the total number of meiotic divisions required to produce 200200 seeds in a typical angiosperm plant.

Solution:

To produce 200200 seeds, we need 200200 pollen grains and 200200 functional megaspores.

  1. Number of meiotic divisions to produce 200200 pollen grains: Since 11 Microspore Mother Cell (MMC) produces 44 pollen grains via meiosis, we need 2004=50\frac{200}{4} = 50 divisions.
  2. Number of meiotic divisions to produce 200200 functional megaspores: Since 11 Megaspore Mother Cell (MMC) produces 44 megaspores but only 11 remains functional, we need 200200 divisions. Total divisions = 50+200=25050 + 200 = 250.

Explanation:

In angiosperms, microsporogenesis results in 4 functional grains per meiosis, whereas megasporogenesis results in only 1 functional megaspore per meiosis due to the degeneration of the other three.

Problem 2:

If the diploid number (2n2n) of a flowering plant is 2424, what will be the chromosome number in the cells of the nucellus, the pollen grain, and the endosperm?

Solution:

Given 2n=242n = 24, then n=12n = 12.

  1. Nucellus (sporophytic tissue): 2n=242n = 24.
  2. Pollen grain (gametophytic tissue): n=12n = 12.
  3. Endosperm (result of triple fusion): 3n=3×12=363n = 3 \times 12 = 36.

Explanation:

The nucellus is part of the ovule (diploid), the pollen grain is the male gametophyte (haploid), and the endosperm is formed by the fusion of three haploid nuclei (triploid).