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Sexual Reproduction in Flowering Plants - Double Fertilization

Grade 12CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Double fertilization is a unique characteristic of angiosperms, first discovered by Nawaschin in LilliumLillium and FritillariaFritillaria.

It involves two types of nuclear fusions: Syngamy and Triple Fusion.

Syngamy: One male gamete (nn) fuses with the egg cell (nn) to form a diploid zygote (2n2n), which eventually develops into the embryo.

Triple Fusion: The second male gamete (nn) fuses with the two polar nuclei (n+nn+n) or the secondary nucleus (2n2n) in the central cell to produce a triploid Primary Endosperm Nucleus (3n3n or PENPEN).

The pollen tube enters the embryo sac through the micropylar end, guided by the filiform apparatus of the synergids.

The central cell after triple fusion becomes the Primary Endosperm Cell (PECPEC) and develops into the endosperm, which provides nutrition to the developing embryo.

The total number of nuclei involved in double fertilization is five (two male gametes, one egg cell, and two polar nuclei).

📐Formulae

1 Male Gamete (n)+1 Egg Cell (n) Zygote (2n)1\text{ Male Gamete } (n) + 1\text{ Egg Cell } (n) \rightarrow \text{ Zygote } (2n)

1 Male Gamete (n)+2 Polar Nuclei (n+n) PEN (3n)1\text{ Male Gamete } (n) + 2\text{ Polar Nuclei } (n+n) \rightarrow \text{ PEN } (3n)

Double Fertilization=Syngamy+Triple Fusion\text{Double Fertilization} = \text{Syngamy} + \text{Triple Fusion}

Ploidy of Endosperm=3n\text{Ploidy of Endosperm} = 3n

💡Examples

Problem 1:

If an angiospermic plant has 2n=242n = 24 chromosomes in its root cells, calculate the number of chromosomes present in the following: (a) Synergids (b) Endosperm (c) Pollen grain.

Solution:

(a) 1212, (b) 3636, (c) 1212.

Explanation:

Root cells are somatic and diploid (2n=242n = 24), so the haploid number n=12n = 12. (a) Synergids are haploid (nn), thus 1212. (b) Endosperm is triploid (3n3n), so 3×12=363 \times 12 = 36. (c) Pollen grains contain male gametes which are haploid (nn), thus 1212.

Problem 2:

How many nuclei are involved in the process of Triple Fusion specifically?

Solution:

33 nuclei.

Explanation:

Triple fusion involves the fusion of one male gamete (nn) and two polar nuclei (n+nn + n) located in the central cell, resulting in a 3n3n nucleus.

Double Fertilization - Revision Notes & Key Diagrams | CBSE Class 12 Biology