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Principles of Inheritance and Variation - Mutation and Genetic Disorders

Grade 12CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Mutation is a phenomenon that results in the alteration of DNA sequences, leading to changes in the genotype and phenotype. It can be caused by mutagens like UV radiation (254 nm254 \text{ nm}), chemicals, or errors during replication.

Point Mutation: A change in a single base pair of DNA. A classic example is Sickle-cell anemia, where the codon GAGGAG (coding for Glutamic acid) is mutated to GUGGUG (coding for Valine) at the sixth position of the β\beta-globin chain.

Frame-shift Mutation: Deletion or insertion of one or two bases changes the reading frame from the point of mutation onwards.

Mendelian Disorders: These are caused by alteration or mutation in a single gene and follow Mendelian inheritance patterns. Examples include Haemophilia (sex-linked recessive), Sickle-cell anemia (autosomal recessive), and Phenylketonuria (PKUPKU).

Chromosomal Disorders: Caused by the absence, excess, or abnormal arrangement of chromosomes. Aneuploidy (gain or loss of chromosomes) occurs due to failure of chromatid segregation during cell division.

Down's Syndrome: Caused by the presence of an additional copy of chromosome number 2121 (Trisomy of 2121). Features include a short stature, furrowed tongue, and partially open mouth.

Klinefelter's Syndrome: Caused by the presence of an additional copy of X-chromosome resulting in a karyotype of 47,XXY47, XXY. These individuals are sterile males with feminine development (Gynaecomastia).

Turner's Syndrome: Caused due to the absence of one of the X chromosomes, resulting in a karyotype of 4545 with X0X0. Affected females are sterile as ovaries are rudimentary.

📐Formulae

Sickle cell hemoglobin transition: GAGGUG\text{Sickle cell hemoglobin transition: } GAG \rightarrow GUG

Trisomy (e.g., Down’s Syndrome): 2n+1=47\text{Trisomy (e.g., Down's Syndrome): } 2n + 1 = 47

Monosomy (e.g., Turner’s Syndrome): 2n1=45\text{Monosomy (e.g., Turner's Syndrome): } 2n - 1 = 45

Klinefelter’s Karyotype: 44A+XXY\text{Klinefelter's Karyotype: } 44A + XXY

Turner’s Karyotype: 44A+X0\text{Turner's Karyotype: } 44A + X0

💡Examples

Problem 1:

A normal-visioned woman whose father was colour blind marries a colour-blind man. What is the probability of their sons being colour blind?

Solution:

50%50\% of the sons will be colour blind.

Explanation:

The woman is a carrier (XCXcX^CX^c) because she inherited the XcX^c allele from her father. The man is colour blind (XcYX^cY). The possible genotypes of offspring are: XCXcX^CX^c (Carrier daughter), XcXcX^cX^c (Colour-blind daughter), XCYX^CY (Normal son), and XcYX^cY (Colour-blind son). Among the sons, the ratio of normal to colour blind is 1:11:1.

Problem 2:

In Sickle-cell anemia, explain the molecular change in the hemoglobin molecule using genetic notation.

Solution:

HbAHbAmutationHbSHbSHb^A Hb^A \xrightarrow{mutation} Hb^S Hb^S

Explanation:

The substitution of amino acid Glutamic acid (GluGlu) by Valine (ValVal) occurs at the sixth position of the β\beta-globin chain of hemoglobin. This is due to a single base substitution at the 6th6^{th} codon of the β\beta-globin gene from GAGGAG to GUGGUG. The mutant hemoglobin molecule undergoes polymerization under low oxygen tension causing the change in the shape of the RBCRBC from biconcave disc to elongated sickle-like structure.

Mutation and Genetic Disorders - Revision Notes & Key Diagrams | CBSE Class 12 Biology