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Human Reproduction - Male Reproductive System

Grade 12CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The male reproductive system is located in the pelvis region and includes a pair of testes, accessory ducts, glands, and the external genitalia.

The testes are situated outside the abdominal cavity within a pouch called the scrotum, which maintains a temperature 22.5C2-2.5^\circ C lower than the internal body temperature, essential for spermatogenesis.

Each testis contains about 250250 testicular lobules, each housing 131-3 highly coiled seminiferous tubules where sperm are produced.

Seminiferous tubules are lined by two types of cells: male germ cells (spermatogonia, 2n2n) and Sertoli cells (nurturing cells).

Leydig cells (interstitial cells) are present in the regions outside the seminiferous tubules and synthesize/secrete testicular hormones called androgens (e.g., Testosterone).

The male accessory ducts include the rete testis, vasa efferentia, epididymis, and vas deferens. The pathway of sperm is: Seminiferous tubules \rightarrow Rete testis \rightarrow Vasa efferentia \rightarrow Epididymis \rightarrow Vas deferens \rightarrow Ejaculatory duct \rightarrow Urethra.

The male accessory glands (seminal vesicles, prostate, and bulbourethral glands) secrete seminal plasma, which is rich in fructose, Ca2+Ca^{2+}, and specific enzymes.

📐Formulae

Semen=Spermatozoa+Seminal Plasma\text{Semen} = \text{Spermatozoa} + \text{Seminal Plasma}

Tscrotum=Tbody(2C to 2.5C)T_{scrotum} = T_{body} - (2^\circ C \text{ to } 2.5^\circ C)

Total Sperm per Ejaculate200 to 300×106\text{Total Sperm per Ejaculate} \approx 200 \text{ to } 300 \times 10^6

Fertility Criteria=(60% normal shape/size)(40% vigorous motility)\text{Fertility Criteria} = (\ge 60\% \text{ normal shape/size}) \cap (\ge 40\% \text{ vigorous motility})

💡Examples

Problem 1:

A male individual produces approximately 250250 million sperm per ejaculate. According to standard physiological requirements for normal fertility, how many of these sperm must exhibit vigorous motility?

Solution:

For normal fertility, at least 40%40\% of the total sperm count must show vigorous motility. Calculation: 40% of 250×106=40100×250,000,000=100,000,00040\% \text{ of } 250 \times 10^6 = \frac{40}{100} \times 250,000,000 = 100,000,000.

Explanation:

As per the NCERT/CBSE guidelines, for normal human fertility, at least 60%60\% of sperm must have normal shape and size, and at least 40%40\% of the total sperm in an ejaculate must show vigorous motility.

Problem 2:

Identify the chromosomal ploidy of the following cells: (i) Spermatogonia, (ii) Primary Spermatocytes, (iii) Secondary Spermatocytes, and (iv) Spermatids.

Solution:

(i) Spermatogonia: 2n2n (4646 chromosomes), (ii) Primary Spermatocytes: 2n2n (4646 chromosomes), (iii) Secondary Spermatocytes: nn (2323 chromosomes), (iv) Spermatids: nn (2323 chromosomes).

Explanation:

Spermatogonia undergo mitosis to form primary spermatocytes (both 2n2n). Primary spermatocytes then undergo Meiosis-I to form haploid (nn) secondary spermatocytes, which undergo Meiosis-II to form haploid (nn) spermatids.

Male Reproductive System - Revision Notes & Key Diagrams | CBSE Class 12 Biology