krit.club logo

Plant Nutrition - Leaf structure

Grade 11A LevelBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

The leaf is the primary organ for photosynthesis, adapted to maximize the absorption of light and the intake of CO2CO_2.

•

The Waxy Cuticle is a waterproof layer that prevents excessive water loss via evaporation while remaining transparent to allow light through.

•

The Upper Epidermis is a thin, transparent layer of cells that protects the inner tissues and allows light to reach the photosynthetic layers.

•

The Palisade Mesophyll consists of tall, columnar cells packed with chloroplasts. They are located near the top of the leaf to maximize light absorption for the reaction 6CO2+6H2O→C6H12O6+6O26CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2.

•

The Spongy Mesophyll contains loosely packed cells with large air spaces, increasing the surface area for the diffusion of CO2CO_2 into cells and O2O_2 out of cells.

•

Stomata are small pores, mostly on the lower epidermis, that allow gas exchange (CO2CO_2 in, O2O_2 and H2OH_2O vapor out).

•

Guard Cells control the opening and closing of stomata to balance gas exchange with the conservation of H2OH_2O.

•

The Vascular Bundle contains the Xylem, which transports H2OH_2O and dissolved mineral ions, and the Phloem, which transports manufactured food like sucrose.

📐Formulae

6CO2+6H2O→chlorophylllightC6H12O6+6O26CO_2 + 6H_2O \xrightarrow[chlorophyll]{light} C_6H_{12}O_6 + 6O_2

Carbon Dioxide+Water→Glucose+Oxygen\text{Carbon Dioxide} + \text{Water} \rightarrow \text{Glucose} + \text{Oxygen}

Rate of Photosynthesis∝1distance2\text{Rate of Photosynthesis} \propto \frac{1}{\text{distance}^2}

💡Examples

Problem 1:

Explain why the palisade mesophyll cells are arranged vertically and packed tightly together.

Solution:

Vertical arrangement and tight packing ensure that a large number of chloroplasts are exposed to direct sunlight. This maximizes the light energy captured to convert H2OH_2O and CO2CO_2 into C6H12O6C_6H_{12}O_6.

Explanation:

The columnar shape allows light to pass through the length of the cell, hitting multiple chloroplasts, which increases the efficiency of the light-dependent stage of photosynthesis.

Problem 2:

A leaf is tested for starch after being kept in the dark for 24 hours. What is the result and why?

Solution:

The iodine test will remain yellow-brown (negative), indicating no starch is present. This is because the plant was 'destarched'.

Explanation:

Without light, the plant cannot perform photosynthesis to produce C6H12O6C_6H_{12}O_6. It converts existing starch reserves back into glucose for respiration to maintain cellular activities, depleting the starch stored in the leaf.

Problem 3:

How does the structure of the spongy mesophyll assist in the movement of CO2CO_2?

Solution:

The large internal surface area and air spaces allow CO2CO_2 to diffuse rapidly from the stomata to the palisade cells.

Explanation:

Diffusion is more efficient in gas than through liquid or cell layers. The air spaces ensure that CO2CO_2 reaches the cell membranes of the mesophyll cells quickly for the photosynthetic reaction.