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Structural Organisation in Animals and Plants - Morphology of Flowering Plants (Root, Stem, Leaf, Inflorescence, Flower, Fruit, Seed)

Grade 11ICSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Root System: Developed from the radicle. Includes Tap root (primary and secondary branches, e.g., Mustard) and Adventitious roots (arising from parts other than the radicle, e.g., Banyan). Regions include: Root cap \rightarrow Region of Meristematic activity \rightarrow Region of Elongation \rightarrow Region of Maturation (with root hairs).

Stem: Developed from the plumule. Characterized by the presence of nodes (where leaves are born) and internodes. Modifications include Underground (storage, e.g., Solanum tuberosumSolanum \text{ tuberosum}), Sub-aerial (vegetative propagation), and Aerial (tendrils, thorns).

Leaf: Originates from shoot apical meristems. Parts: Leaf base, Petiole, and Lamina. Venation: Reticulate (network, e.g., Dicots) and Parallel (veins run parallel, e.g., Monocots). Phyllotaxy: Arrangement of leaves on stem—Alternate, Opposite, or Whorled.

Inflorescence: Arrangement of flowers on the floral axis (peduncle). Two types: Racemose (main axis continues to grow, flowers in acropetal succession) and Cymose (main axis terminates in a flower, flowers in basipetal succession).

Flower: The reproductive unit. Parts: Calyx (KK), Corolla (CC), Androecium (AA), and Gynoecium (GG). Symmetry: Actinomorphic (radial, \oplus) and Zygomorphic (bilateral, %\%).

Ovary Position: Hypogynous (Superior ovary G\underline{G}), Perigynous (Half-inferior ovary), and Epigynous (Inferior ovary G\overline{G}).

Placentation: Arrangement of ovules within the ovary. Types: Marginal (Pea), Axile (China rose), Parietal (Mustard), Free central (Primrose), and Basal (Sunflower).

Fruit and Seed: Fruit is a ripened ovary. In Monocots (e.g., Maize), the seed coat is fused with the fruit wall and contains a single large cotyledon called the Scutellum. Dicots (e.g., Pea) have two cotyledons and a non-endospermic nature in many cases.

📐Formulae

Fabaceae: %⚥ K(5)C1+2+(2)A(9)+1G1\text{Fabaceae: } \% \text{⚥ } K_{(5)} C_{1+2+(2)} A_{(9)+1} \underline{G}_{1}

Solanaceae: ⚥ K(5)C(5)A5^G(2)\text{Solanaceae: } \oplus \text{⚥ } K_{(5)} \widehat{C_{(5)} A_5} \underline{G}_{(2)}

Liliaceae: Br⚥ P(3+3)A3+3G(3)\text{Liliaceae: } Br \oplus \text{⚥ } P_{(3+3)} A_{3+3} \underline{G}_{(3)}

Floral formula symbols: =Actinomorphic, %=Zygomorphic, ⚥=Bisexual\text{Floral formula symbols: } \oplus = \text{Actinomorphic, } \% = \text{Zygomorphic, } \text{⚥} = \text{Bisexual}

💡Examples

Problem 1:

Identify the type of placentation and floral symmetry for a plant with the floral formula ⚥ K(5)C(5)A5^G(2)\oplus \text{⚥ } K_{(5)} \widehat{C_{(5)} A_5} \underline{G}_{(2)}.

Solution:

The plant belongs to the family Solanaceae. Symmetry: Actinomorphic (\oplus). Placentation: Axile.

Explanation:

In Solanaceae, the ovary is superior (G\underline{G}), bicarpellary, syncarpous, and the placentation is axile with a swollen placenta.

Problem 2:

Calculate the number of stamens and their arrangement in the family Fabaceae based on its formula.

Solution:

Total stamens = 1010. Arrangement: Diadelphous (9)+1(9) + 1.

Explanation:

The formula A(9)+1A_{(9)+1} indicates that 99 stamens are fused into one bundle and 11 stamen remains free, which is the characteristic diadelphous condition.

Problem 3:

Distinguish between the venation of Zea maysZea \text{ mays} and Hibiscus rosa-sinensisHibiscus \text{ rosa-sinensis}.

Solution:

Zea maysZea \text{ mays} (Maize) has parallel venation; HibiscusHibiscus (China rose) has reticulate venation.

Explanation:

Maize is a Monocot, which typically displays parallel venation, while China rose is a Dicot, displaying reticulate venation.

Morphology of Flowering Plants (Root, Stem, Leaf, Inflorescence, Flower, Fruit, Seed) Revision…