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Metabolism, Cell Respiration and Photosynthesis (AHL) - Photosynthesis (HL)

Grade 11IBBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Photosynthesis occurs in two main stages: the Light-Dependent Reactions (in the thylakoid membrane) and the Light-Independent Reactions (in the stroma).

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Light-Dependent Reactions involve the absorption of light by photosystems (PSIIPSII and PSIPSI). Photolysis of H2OH_2O occurs at PSIIPSII, releasing O2O_2, protons (H+H^+), and electrons (e−e^-).

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Photophosphorylation: The flow of electrons through the Electron Transport Chain (ETCETC) generates a proton gradient. H+H^+ ions flow through ATPATP synthase to produce ATPATP from ADPADP and PiP_i.

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Reduction of NADPNADP: PSIPSI absorbs light to excite electrons, which are then used to reduce NADP+NADP^+ to NADPHNADPH via the enzyme NADPNADP reductase.

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Light-Independent Reactions (Calvin Cycle): CO2CO_2 is fixed to Ribulose bisphosphate (RuBPRuBP) by the enzyme Rubisco, forming two molecules of Glycerate-3-phosphate (G3PG3P).

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Reduction Phase: G3PG3P is reduced to Triose Phosphate (TPTP) using ATPATP and NADPHNADPH produced in the light-dependent stage.

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Regeneration: For every six molecules of TPTP produced, five are used to regenerate RuBPRuBP (requiring ATPATP), while one exits the cycle to contribute to the formation of glucose (C6H12O6C_6H_{12}O_6).

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Chloroplast Structure: The thylakoids provide a large surface area for light absorption; the small thylakoid lumen allows for rapid accumulation of a proton gradient; the stroma contains the enzymes for the Calvin cycle.

📐Formulae

6CO2+6H2O→lightC6H12O6+6O26CO_2 + 6H_2O \xrightarrow{light} C_6H_{12}O_6 + 6O_2

2H2O→photolysis4e−+4H++O22H_2O \xrightarrow{photolysis} 4e^- + 4H^+ + O_2

NADP++2e−+H+→NADPHNADP^+ + 2e^- + H^+ \rightarrow NADPH

ADP+Pi→ATP+H2OADP + P_i \rightarrow ATP + H_2O

RuBP+CO2→Rubisco2×G3PRuBP + CO_2 \xrightarrow{Rubisco} 2 \times G3P

💡Examples

Problem 1:

Determine the total requirements of ATPATP and NADPHNADPH for the synthesis of one molecule of glucose (C6H12O6C_6H_{12}O_6) via the Calvin cycle.

Solution:

18 ATP18 \text{ ATP} and 12 NADPH12 \text{ NADPH}.

Explanation:

For every one molecule of CO2CO_2 fixed, the Calvin cycle requires 3 ATP3 \text{ ATP} (22 for reducing G3PG3P to TPTP and 11 for regenerating RuBPRuBP) and 2 NADPH2 \text{ NADPH} (for reducing G3PG3P to TPTP). Since glucose is a hexose sugar containing 66 carbon atoms, 66 molecules of CO2CO_2 must be fixed. Calculation: 6×3=18 ATP6 \times 3 = 18 \text{ ATP} and 6×2=12 NADPH6 \times 2 = 12 \text{ NADPH}.

Problem 2:

Explain why the pH of the thylakoid lumen decreases during the light-dependent reactions.

Solution:

The pH decreases due to the accumulation of H+H^+ ions.

Explanation:

Proton concentration increases in the lumen through two mechanisms: 1. The photolysis of water (H2O→2H++2e−+12O2H_2O \rightarrow 2H^+ + 2e^- + \frac{1}{2}O_2) and 2. The active transport of H+H^+ from the stroma to the lumen by the ETCETC (plastoquinone). A high [H+][H^+] results in a lower pH, creating the electrochemical gradient necessary for chemiosmosis.