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Respiration in Plants - Fermentation (anaerobic)

Grade 11CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Fermentation is a form of anaerobic respiration that involves the incomplete oxidation of glucose under anaerobic conditions (absence of O2O_2).

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The process takes place entirely in the cytoplasm of the cell.

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In alcoholic fermentation, pyruvic acid (CH3COCOOHCH_3COCOOH) is converted into ethanol (C2H5OHC_2H_5OH) and CO2CO_2 in a two-step process catalyzed by the enzymes pyruvic acid decarboxylase and alcohol dehydrogenase.

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In lactic acid fermentation, certain bacteria and animal muscle cells (during vigorous exercise) convert pyruvic acid into lactic acid (CH3CH(OH)COOHCH_3CH(OH)COOH) using the enzyme lactate dehydrogenase.

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A crucial step in both types of fermentation is the re-oxidation of NADH+H+NADH + H^+ back to NAD+NAD^+, which allows glycolysis to continue in the absence of oxygen.

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The energy released during fermentation is very low; less than 7%7\% of the energy in glucose is released, and the net gain is only 2 molecules of ATPATP per molecule of glucose.

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Yeast poisons themselves to death when the concentration of alcohol reaches about 13%13\%.

📐Formulae

Alcoholic Fermentation: C6H12O6→Glycolysis2CH3COCOOH→Decarboxylase/Dehydrogenase2C2H5OH+2CO2+2ATP\text{Alcoholic Fermentation: } C_6H_{12}O_6 \xrightarrow{\text{Glycolysis}} 2CH_3COCOOH \xrightarrow{\text{Decarboxylase/Dehydrogenase}} 2C_2H_5OH + 2CO_2 + 2ATP

Lactic Acid Fermentation: C6H12O6→Glycolysis2CH3COCOOH→Lactate dehydrogenase2CH3CH(OH)COOH+2ATP\text{Lactic Acid Fermentation: } C_6H_{12}O_6 \xrightarrow{\text{Glycolysis}} 2CH_3COCOOH \xrightarrow{\text{Lactate dehydrogenase}} 2CH_3CH(OH)COOH + 2ATP

Net ATP Gain: 2 molecules of ATP per glucose molecule\text{Net ATP Gain: } 2 \text{ molecules of } ATP \text{ per glucose molecule}

Redox Step: NADH+H+→NAD++2H++2e−\text{Redox Step: } NADH + H^+ \rightarrow NAD^+ + 2H^+ + 2e^-

💡Examples

Problem 1:

Calculate the net gain of ATPATP when 5 molecules of glucose undergo fermentation in a yeast cell.

Solution:

10 ATPATP

Explanation:

In fermentation, one molecule of glucose yields a net gain of 2 ATPATP molecules (produced during glycolysis). Therefore, for 5 molecules of glucose: 5×2=105 \times 2 = 10 ATPATP.

Problem 2:

Name the enzymes involved in the conversion of pyruvic acid to ethanol and identify the byproduct released.

Solution:

Enzymes: Pyruvic acid decarboxylase and Alcohol dehydrogenase; Byproduct: CO2CO_2.

Explanation:

Pyruvic acid (CH3COCOOHCH_3COCOOH) first undergoes decarboxylation to form acetaldehyde and CO2CO_2 via pyruvic acid decarboxylase. Then, acetaldehyde is reduced to ethanol by alcohol dehydrogenase using NADHNADH.

Fermentation (anaerobic) Class 11 Notes & Examples