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Respiration in Plants - Fermentation (anaerobic)

Grade 11CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Fermentation is a form of anaerobic respiration that involves the incomplete oxidation of glucose under anaerobic conditions (absence of O2O_2).

The process takes place entirely in the cytoplasm of the cell.

In alcoholic fermentation, pyruvic acid (CH3COCOOHCH_3COCOOH) is converted into ethanol (C2H5OHC_2H_5OH) and CO2CO_2 in a two-step process catalyzed by the enzymes pyruvic acid decarboxylase and alcohol dehydrogenase.

In lactic acid fermentation, certain bacteria and animal muscle cells (during vigorous exercise) convert pyruvic acid into lactic acid (CH3CH(OH)COOHCH_3CH(OH)COOH) using the enzyme lactate dehydrogenase.

A crucial step in both types of fermentation is the re-oxidation of NADH+H+NADH + H^+ back to NAD+NAD^+, which allows glycolysis to continue in the absence of oxygen.

The energy released during fermentation is very low; less than 7%7\% of the energy in glucose is released, and the net gain is only 2 molecules of ATPATP per molecule of glucose.

Yeast poisons themselves to death when the concentration of alcohol reaches about 13%13\%.

📐Formulae

Alcoholic Fermentation: C6H12O6Glycolysis2CH3COCOOHDecarboxylase/Dehydrogenase2C2H5OH+2CO2+2ATP\text{Alcoholic Fermentation: } C_6H_{12}O_6 \xrightarrow{\text{Glycolysis}} 2CH_3COCOOH \xrightarrow{\text{Decarboxylase/Dehydrogenase}} 2C_2H_5OH + 2CO_2 + 2ATP

Lactic Acid Fermentation: C6H12O6Glycolysis2CH3COCOOHLactate dehydrogenase2CH3CH(OH)COOH+2ATP\text{Lactic Acid Fermentation: } C_6H_{12}O_6 \xrightarrow{\text{Glycolysis}} 2CH_3COCOOH \xrightarrow{\text{Lactate dehydrogenase}} 2CH_3CH(OH)COOH + 2ATP

Net ATP Gain: 2 molecules of ATP per glucose molecule\text{Net ATP Gain: } 2 \text{ molecules of } ATP \text{ per glucose molecule}

Redox Step: NADH+H+NAD++2H++2e\text{Redox Step: } NADH + H^+ \rightarrow NAD^+ + 2H^+ + 2e^-

💡Examples

Problem 1:

Calculate the net gain of ATPATP when 5 molecules of glucose undergo fermentation in a yeast cell.

Solution:

10 ATPATP

Explanation:

In fermentation, one molecule of glucose yields a net gain of 2 ATPATP molecules (produced during glycolysis). Therefore, for 5 molecules of glucose: 5×2=105 \times 2 = 10 ATPATP.

Problem 2:

Name the enzymes involved in the conversion of pyruvic acid to ethanol and identify the byproduct released.

Solution:

Enzymes: Pyruvic acid decarboxylase and Alcohol dehydrogenase; Byproduct: CO2CO_2.

Explanation:

Pyruvic acid (CH3COCOOHCH_3COCOOH) first undergoes decarboxylation to form acetaldehyde and CO2CO_2 via pyruvic acid decarboxylase. Then, acetaldehyde is reduced to ethanol by alcohol dehydrogenase using NADHNADH.

Fermentation (anaerobic) - Revision Notes & Key Diagrams | CBSE Class 11 Biology