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Body Fluids and Circulation - Cardiac cycle, cardiac output, ECG

Grade 11CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Cardiac Cycle is the sequential event in the heart which is cyclically repeated and consists of systole (contraction) and diastole (relaxation) of both the atria and ventricles. The total duration for one cycle is approximately 0.80.8 seconds.

Joint Diastole: All four chambers of the heart are in a relaxed state. The tricuspid and bicuspid valves are open, allowing blood from pulmonary veins and vena cava to flow into the left and right ventricles respectively through the atria. Semilunar valves are closed at this stage.

Atrial Systole (0.10.1 s): The SA node generates an action potential which stimulates both the atria to undergo a simultaneous contraction. This increases the flow of blood into the ventricles by about 30%30\%.

Ventricular Systole (0.30.3 s): The action potential is conducted to the ventricular side by the AV node and AV bundle. Ventricular contraction increases ventricular pressure, causing the closure of tricuspid and bicuspid valves (producing the first heart sound: 'Lubb'). This is followed by the opening of semilunar valves as pressure rises, forcing blood into the circulatory pathways.

Ventricular Diastole (0.40.4 s): The ventricles relax and ventricular pressure falls, causing the closure of semilunar valves (producing the second heart sound: 'Dupp').

Stroke Volume (SV): Each ventricle pumps out approximately 7070 mL of blood during a cardiac cycle, which is called the stroke volume.

Cardiac Output (CO): It is the volume of blood pumped out by each ventricle per minute. For a healthy individual, it is roughly 50005000 mL or 55 L.

Electrocardiogram (ECG): A graphical representation of the electrical activity of the heart. The P-wave represents atrial depolarisation (excitation). The QRS complex represents ventricular depolarisation. The T-wave represents ventricular repolarisation (return to excited to normal state).

📐Formulae

Cardiac Output (CO)=Stroke Volume (SV)×Heart Rate (HR)Cardiac\ Output\ (CO) = Stroke\ Volume\ (SV) \times Heart\ Rate\ (HR)

Stroke Volume (SV)=End Diastolic Volume (EDV)End Systolic Volume (ESV)Stroke\ Volume\ (SV) = End\ Diastolic\ Volume\ (EDV) - End\ Systolic\ Volume\ (ESV)

Duration of cardiac cycle=60 secondsHeart Rate (beats/min)Duration\ of\ cardiac\ cycle = \frac{60\ seconds}{Heart\ Rate\ (beats/min)}

Average CO70 mL/beat×72 beats/min5040 mL/minAverage\ CO \approx 70\ mL/beat \times 72\ beats/min \approx 5040\ mL/min

💡Examples

Problem 1:

An athlete has a resting heart rate of 5050 beats per minute and a stroke volume of 100100 mL. Calculate his cardiac output and compare it with an ordinary man having a heart rate of 7272 beats per minute and a stroke volume of 7070 mL.

Solution:

For the athlete: CO=50 beats/min×100 mL/beat=5,000 mL/min=5 L/minCO = 50\ beats/min \times 100\ mL/beat = 5,000\ mL/min = 5\ L/min. For the ordinary man: CO=72 beats/min×70 mL/beat=5,040 mL/min5 L/minCO = 72\ beats/min \times 70\ mL/beat = 5,040\ mL/min \approx 5\ L/min.

Explanation:

Even though the athlete's heart rate is lower (bradycardia typical of trained athletes), the increased efficiency represented by a higher stroke volume (100100 mL vs 7070 mL) allows the athlete to maintain a similar cardiac output as a normal person.

Problem 2:

During a clinical checkup, a patient's ECG shows an abnormally high number of QRS complexes within a 11 minute interval. What does this indicate?

Solution:

A higher number of QRSQRS complexes indicates a higher heart rate (HR>100HR > 100 beats/min), a condition known as tachycardia.

Explanation:

Since each QRSQRS complex corresponds to one ventricular contraction (one heartbeat), counting the number of QRSQRS complexes in a given time period is the standard method to determine the heart rate of an individual.

Cardiac cycle, cardiac output, ECG - Revision Notes & Key Diagrams | CBSE Class 11 Biology