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Physics - Nuclear physics (Radioactivity and half-life)

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Radioactivity is the spontaneous emission of radiation from an unstable nucleus. It is a random process, meaning we cannot predict which individual nucleus will decay at any given time.

The structure of an atom is represented as ZAX^A_Z X, where AA is the nucleon (mass) number and ZZ is the proton (atomic) number.

Alpha particles (α\alpha) consist of 2 protons and 2 neutrons, represented as 24extHe^4_2 ext{He}. They are highly ionizing but have low penetration power (stopped by paper).

Beta particles (β\beta) are high-speed electrons emitted from the nucleus when a neutron turns into a proton, represented as 10exte^0_{-1} ext{e}. They have moderate ionizing and penetration power (stopped by aluminum).

Gamma rays (γ\gamma) are high-energy electromagnetic waves. They have low ionizing power but high penetration power (reduced by thick lead or concrete).

The Half-life (t1/2t_{1/2}) of a radioactive isotope is the time taken for half of the nuclei in a sample to decay, or the time taken for the activity (measured in Becquerels, BqBq) to fall to half of its initial value.

Background radiation is the low-level ionizing radiation that is constantly present in the environment from natural sources (radon gas, cosmic rays, rocks) and man-made sources (medical X-rays, nuclear fallout).

📐Formulae

Alpha Decay: ZAXZ2A4Y+24He\text{Alpha Decay: } ^A_Z X \rightarrow ^{A-4}_{Z-2} Y + ^4_2\text{He}

Beta Decay: ZAXZ+1AY+10e\text{Beta Decay: } ^A_Z X \rightarrow ^{A}_{Z+1} Y + ^0_{-1}\text{e}

Number of Half-lives (n)=Total Time ElapsedHalf-life (t1/2)\text{Number of Half-lives } (n) = \frac{\text{Total Time Elapsed}}{\text{Half-life } (t_{1/2})}

Final Activity=Initial Activity2n\text{Final Activity} = \frac{\text{Initial Activity}}{2^n}

💡Examples

Problem 1:

A radioactive sample has an initial activity of 1200 Bq1200\text{ Bq}. If the half-life of the isotope is 5 days5\text{ days}, calculate the activity of the sample after 15 days15\text{ days}.

Solution:

  1. Find the number of half-lives: n=15 days5 days=3n = \frac{15\text{ days}}{5\text{ days}} = 3.
  2. Apply the decay: After 1 half-life: 1200/2=600 Bq1200 / 2 = 600\text{ Bq} After 2 half-lives: 600/2=300 Bq600 / 2 = 300\text{ Bq} After 3 half-lives: 300/2=150 Bq300 / 2 = 150\text{ Bq}

Explanation:

After three half-lives, the activity halves three times, resulting in 123=18\frac{1}{2^3} = \frac{1}{8} of the original activity.

Problem 2:

Complete the following nuclear equation: 88226Ra86222Rn+?^{226}_{88}\text{Ra} \rightarrow ^{222}_{86}\text{Rn} + ?

Solution:

88226Ra86222Rn+24He^{226}_{88}\text{Ra} \rightarrow ^{222}_{86}\text{Rn} + ^4_2\text{He}

Explanation:

To balance the equation, the nucleon number on the right must sum to 226226 (222+4=226222 + 4 = 226) and the proton number must sum to 8888 (86+2=8886 + 2 = 88). This corresponds to the emission of an alpha particle.

Nuclear physics (Radioactivity and half-life) Revision - Grade 9 Science IGCSE