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Physics - Electromagnetism (Magnetic fields and Motors)

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Magnetic field lines originate from the North (NN) pole and terminate at the South (SS) pole. The density of lines indicates the strength of the field (BB).

The magnetic field around a straight current-carrying wire forms concentric circles. Its direction is determined by the Right-Hand Grip Rule: Thumb points to current (II), fingers curl in the direction of the field (BB).

A solenoid is a long coil of wire. The field inside is strong and uniform. Strength can be increased by increasing the current (II), increasing the number of turns (NN), or adding a soft iron core.

The Motor Effect: When a current-carrying conductor is placed in an external magnetic field, it experiences a force (FF) due to the interaction of the fields.

Fleming's Left-Hand Rule determines the direction of the force: Thumb = Force/Motion (FF), First Finger = Magnetic Field (BB from NN to SS), Second Finger = Current (II from ++ to -).

In a DC Motor, a split-ring commutator reverses the direction of the current every half-turn to ensure the coil continues to rotate in the same direction.

The magnitude of the force on a wire is proportional to the magnetic flux density (BB), the current (II), and the length of the wire (LL) within the field.

📐Formulae

F=BILF = BIL

Strength of solenoidN×I\text{Strength of solenoid} \propto N \times I

B=Magnetic Flux Density (measured in Teslas, T)B = \text{Magnetic Flux Density (measured in Teslas, } T)

💡Examples

Problem 1:

A wire of length L=0.2 mL = 0.2\text{ m} is placed perpendicular to a magnetic field with a flux density B=0.5 TB = 0.5\text{ T}. If a current I=3.0 AI = 3.0\text{ A} flows through the wire, calculate the magnitude of the magnetic force FF acting on it.

Solution:

F=0.5×3.0×0.2=0.3 NF = 0.5 \times 3.0 \times 0.2 = 0.3\text{ N}

Explanation:

Using the formula F=BILF = BIL, substitute the given values: B=0.5B = 0.5, I=3.0I = 3.0, and L=0.2L = 0.2. The resulting force is 0.3 Newtons0.3\text{ Newtons}.

Problem 2:

Identify the direction of the force on a wire where the current is flowing horizontally to the right and the magnetic field lines are pointing vertically downwards into the page.

Solution:

The force is directed towards the viewer (out of the page).

Explanation:

Using Fleming's Left-Hand Rule: Point the first finger (Field) downwards into the page, point the second finger (Current) to the right. The thumb (Force) will point upwards, out of the plane of the page.

Electromagnetism (Magnetic fields and Motors) Revision - Grade 9 Science IGCSE