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Physics - Electromagnetism (Magnetic fields and Motors)

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Magnetic field lines originate from the North (NN) pole and terminate at the South (SS) pole. The density of lines indicates the strength of the field (BB).

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The magnetic field around a straight current-carrying wire forms concentric circles. Its direction is determined by the Right-Hand Grip Rule: Thumb points to current (II), fingers curl in the direction of the field (BB).

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A solenoid is a long coil of wire. The field inside is strong and uniform. Strength can be increased by increasing the current (II), increasing the number of turns (NN), or adding a soft iron core.

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The Motor Effect: When a current-carrying conductor is placed in an external magnetic field, it experiences a force (FF) due to the interaction of the fields.

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Fleming's Left-Hand Rule determines the direction of the force: Thumb = Force/Motion (FF), First Finger = Magnetic Field (BB from NN to SS), Second Finger = Current (II from ++ to −-).

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In a DC Motor, a split-ring commutator reverses the direction of the current every half-turn to ensure the coil continues to rotate in the same direction.

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The magnitude of the force on a wire is proportional to the magnetic flux density (BB), the current (II), and the length of the wire (LL) within the field.

📐Formulae

F=BILF = BIL

Strength of solenoid∝N×I\text{Strength of solenoid} \propto N \times I

B=Magnetic Flux Density (measured in Teslas, T)B = \text{Magnetic Flux Density (measured in Teslas, } T)

💡Examples

Problem 1:

A wire of length L=0.2 mL = 0.2\text{ m} is placed perpendicular to a magnetic field with a flux density B=0.5 TB = 0.5\text{ T}. If a current I=3.0 AI = 3.0\text{ A} flows through the wire, calculate the magnitude of the magnetic force FF acting on it.

Solution:

F=0.5×3.0×0.2=0.3 NF = 0.5 \times 3.0 \times 0.2 = 0.3\text{ N}

Explanation:

Using the formula F=BILF = BIL, substitute the given values: B=0.5B = 0.5, I=3.0I = 3.0, and L=0.2L = 0.2. The resulting force is 0.3 Newtons0.3\text{ Newtons}.

Problem 2:

Identify the direction of the force on a wire where the current is flowing horizontally to the right and the magnetic field lines are pointing vertically downwards into the page.

Solution:

The force is directed towards the viewer (out of the page).

Explanation:

Using Fleming's Left-Hand Rule: Point the first finger (Field) downwards into the page, point the second finger (Current) to the right. The thumb (Force) will point upwards, out of the plane of the page.