krit.club logo

Chemistry - The Periodic Table (Group properties and Transition elements)

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Periodic Table is arranged in order of increasing atomic number (ZZ). Periods represent the number of electron shells, while Groups represent the number of valence electrons.

Group 1 (Alkali Metals): These are soft metals with low densities. Reactivity increases down the group because the outer electron is further from the nucleus, experiencing less attraction and thus is easier to lose (MM++eM \rightarrow M^+ + e^-).

Group 7 (Halogens): These are non-metals that exist as diatomic molecules (e.g., F2F_2, Cl2Cl_2). Reactivity decreases down the group as it becomes harder to attract an incoming electron into the shell further from the nucleus.

Displacement Reactions: A more reactive halogen will displace a less reactive halogen from its halide solution. For example, Cl2Cl_2 will displace BrBr^- from KBrKBr.

Group 0 (Noble Gases): These are monatomic gases with a full outer shell of electrons (88 electrons, except HeHe which has 22). They are chemically inert/unreactive.

Transition Elements: Metals located in the center of the table. Characteristics include: high melting points, high density, formation of colored compounds (e.g., Cu2+Cu^{2+} is blue), and use as catalysts (e.g., FeFe in the Haber process).

Variable Oxidation States: Unlike Group 1 metals which only form +1+1 ions, transition metals can form multiple ions, such as Fe2+Fe^{2+} and Fe3+Fe^{3+}.

📐Formulae

2M(s)+2H2O(l)2MOH(aq)+H2(g)2M(s) + 2H_2O(l) \rightarrow 2MOH(aq) + H_2(g) (Group 1 Reaction with water)

Cl2(g)+2KI(aq)2KCl(aq)+I2(aq)Cl_2(g) + 2KI(aq) \rightarrow 2KCl(aq) + I_2(aq) (Halogen Displacement)

X2+2e2XX_2 + 2e^- \rightarrow 2X^- (Reduction of a Halogen atom)

MM++eM \rightarrow M^+ + e^- (Oxidation of an Alkali Metal)

💡Examples

Problem 1:

Predict the observation and write the chemical equation when a small piece of Sodium (NaNa) is added to water containing universal indicator.

Solution:

2Na(s)+2H2O(l)2NaOH(aq)+H2(g)2Na(s) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g)

Explanation:

Observations include the sodium melting into a ball, fizzing (due to H2H_2 gas), and the indicator turning purple/blue because NaOHNaOH is a strong alkali (OHOH^- ions).

Problem 2:

Explain why the boiling point of Halogens increases as you move down Group 7 from Fluorine (F2F_2) to Iodine (I2I_2).

Solution:

F2<Cl2<Br2<I2F_2 < Cl_2 < Br_2 < I_2

Explanation:

As you go down the group, the molecular size increases and the number of electrons increases. This leads to stronger intermolecular forces (Van der Waals forces), which require more thermal energy to overcome, changing the state from gas (Cl2Cl_2) to liquid (Br2Br_2) to solid (I2I_2).

Problem 3:

Identify the transition metal catalyst used in the manufacture of ammonia and the oxidation states of Iron in FeOFeO and Fe2O3Fe_2O_3.

Solution:

Catalyst: FeFe; Oxidation states: Fe2+Fe^{2+} in FeOFeO and Fe3+Fe^{3+} in Fe2O3Fe_2O_3.

Explanation:

Transition metals are defined by their ability to provide surface area for catalysis and their variable valency. In FeOFeO, oxygen is 22-, so FeFe is +2+2. In Fe2O3Fe_2O_3, total oxygen charge is 3×(2)=63 \times (-2) = -6, so 2×Fe=+62 \times Fe = +6, making Fe=+3Fe = +3.