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Chemistry - Electrochemistry (Electrolysis and electroplating)

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Electrolysis is the breakdown of an ionic compound, molten or in aqueous solution, by the passage of electricity. The substance being decomposed is called the electrolyte.

The Anode is the positive electrode where oxidation occurs (loss of electrons). The Cathode is the negative electrode where reduction occurs (gain of electrons). Remember the mnemonic OIL RIG (Oxidation Is Loss, Reduction Is Gain).

In the electrolysis of molten salts, such as molten PbBr2PbBr_2, the metal is produced at the cathode (Pb2++2ePbPb^{2+} + 2e^- \rightarrow Pb) and the non-metal at the anode (2BrBr2+2e2Br^- \rightarrow Br_2 + 2e^-).

In aqueous solutions, water provides H+H^+ and OHOH^- ions. At the cathode, H2H_2 gas is produced if the metal in the salt is more reactive than hydrogen (e.g., NaNa, KK, MgMg). If the metal is less reactive (e.g., CuCu, AgAg), the metal is deposited.

At the anode in aqueous solutions, oxygen gas (O2O_2) is produced from OHOH^- ions unless the solution contains a high concentration of halide ions (ClCl^-, BrBr^-, II^-), in which case the halogen is produced.

Electroplating is the process of coating a metal object with a thin layer of another metal using electrolysis. The object to be plated is made the cathode, and the plating metal is made the anode. The electrolyte must be a solution of a soluble salt of the plating metal.

In the refining of Copper, an impure copper anode dissolves into the electrolyte, and pure copper atoms are deposited onto the cathode: Cu2+(aq)+2eCu(s)Cu^{2+}(aq) + 2e^- \rightarrow Cu(s).

📐Formulae

Mn++neM(s)M^{n+} + ne^- \rightarrow M(s) (General reduction at Cathode)

2XX2(g)+2e2X^- \rightarrow X_2(g) + 2e^- (General oxidation of halides at Anode)

4OH(aq)2H2O(l)+O2(g)+4e4OH^-(aq) \rightarrow 2H_2O(l) + O_2(g) + 4e^- (Discharge of hydroxide ions)

2H+(aq)+2eH2(g)2H^+(aq) + 2e^- \rightarrow H_2(g) (Discharge of hydrogen ions)

💡Examples

Problem 1:

Predict the products at the anode and cathode during the electrolysis of concentrated aqueous sodium chloride (NaClNaCl), also known as brine.

Solution:

Cathode: H2(g)H_2(g); Anode: Cl2(g)Cl_2(g).

Explanation:

In aqueous NaClNaCl, ions present are Na+Na^+, ClCl^-, H+H^+, and OHOH^-. At the cathode, H+H^+ is less reactive than Na+Na^+, so it is discharged to form H2H_2 gas. At the anode, because the solution is concentrated, ClCl^- ions are discharged preferentially over OHOH^- to form Cl2Cl_2 gas.

Problem 2:

Describe how to electroplate a steel spoon with silver (AgAg).

Solution:

Cathode: Steel spoon; Anode: Pure silver rod; Electrolyte: Silver nitrate solution (AgNO3AgNO_3).

Explanation:

The spoon is the cathode where Ag+Ag^+ ions gain electrons to form silver metal: Ag+(aq)+eAg(s)Ag^+(aq) + e^- \rightarrow Ag(s). The silver anode dissolves to replenish the ions: Ag(s)Ag+(aq)+eAg(s) \rightarrow Ag^+(aq) + e^-. This results in a layer of silver coating the spoon.