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Introduction to Organic Chemistry - Hydrocarbons and Functional Groups

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Organic chemistry is the study of carbon-based compounds. Carbon is unique because it can form four covalent bonds, allowing for the formation of long chains and rings (catenation).

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Hydrocarbons are compounds consisting entirely of hydrogen and carbon atoms. They are classified into saturated (C−CC-C single bonds) and unsaturated (containing C=CC=C double or C≡CC \equiv C triple bonds).

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A Homologous Series is a family of organic compounds with the same general formula, similar chemical properties, and a graduation in physical properties (like boiling point) as the chain length increases.

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Alkanes are saturated hydrocarbons with the general formula CnH2n+2C_nH_{2n+2}. They are relatively unreactive except for combustion and substitution reactions with halogens under UVUV light.

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Alkenes are unsaturated hydrocarbons containing at least one C=CC=C double bond, with the general formula CnH2nC_nH_{2n}. They are more reactive than alkanes and undergo addition reactions.

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Functional Groups are specific atoms or groups of atoms within molecules that determine the chemical reactivity of the molecule. Examples include the hydroxyl group (−OH-OH) in alcohols and the carboxyl group (−COOH-COOH) in carboxylic acids.

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Isomers are molecules that have the same molecular formula but different structural arrangements (e.g., but−1−enebut-1-ene and but−2−enebut-2-ene).

📐Formulae

CnH2n+2 (General formula for Alkanes)C_nH_{2n+2} \text{ (General formula for Alkanes)}

CnH2n (General formula for Alkenes)C_nH_{2n} \text{ (General formula for Alkenes)}

CnH2n−2 (General formula for Alkynes)C_nH_{2n-2} \text{ (General formula for Alkynes)}

CnH2n+1OH (General formula for Alcohols)C_nH_{2n+1}OH \text{ (General formula for Alcohols)}

CnH2n+1COOH (General formula for Carboxylic Acids, where n≥0)C_nH_{2n+1}COOH \text{ (General formula for Carboxylic Acids, where } n \ge 0)

💡Examples

Problem 1:

Identify the name and molecular formula of an alkane containing 55 carbon atoms.

Solution:

Pentane, C5H12C_5H_{12}

Explanation:

Using the general formula CnH2n+2C_nH_{2n+2} where n=5n=5, we calculate H=(2×5)+2=12H = (2 \times 5) + 2 = 12. The prefix for 5 carbons is 'pent-', and the suffix for alkanes is '-ane'.

Problem 2:

Describe the chemical test to distinguish between C2H6C_2H_6 and C2H4C_2H_4.

Solution:

Add bromine water (Br2(aq)Br_2(aq)) to both substances.

Explanation:

Ethane (C2H6C_2H_6) is an alkane and will not react with bromine water (it remains orange/brown). Ethene (C2H4C_2H_4) is an alkene; it undergoes an addition reaction, decolorizing the bromine water from orange to colorless.

Problem 3:

Draw and name the structural isomer of C4H10C_4H_{10} that is not a straight chain.

Solution:

2-methylpropane, CH3CH(CH3)CH3CH_3CH(CH_3)CH_3

Explanation:

While butane is a straight chain of 4 carbons, 2-methylpropane (also called isobutane) consists of a 3-carbon main chain with a methyl group (−CH3-CH_3) attached to the second carbon.