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Genetics - Chromosomes and Genes

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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DNA (DeoxyribonucleicacidDeoxyribonucleic acid) is the molecule that carries genetic information. It consists of two strands forming a double helix, with a backbone of phosphate and deoxyribose sugar.

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The four nitrogenous bases in DNADNA are Adenine (AA), Thymine (TT), Cytosine (CC), and Guanine (GG). They follow complementary base-pairing rules: AA pairs with TT and CC pairs with GG.

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Chromosomes are long, coiled structures of DNADNA and proteins (histones) found in the nucleus. Humans typically have 2323 pairs of chromosomes (4646 total).

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A gene is a specific segment of DNADNA that codes for a particular protein, which determines a specific trait in an organism.

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Alleles are different versions of the same gene (e.g., the gene for eye color may have a blue allele or a brown allele).

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Genotype represents the genetic makeup (e.g., AAAA, AaAa, or aaaa), while Phenotype refers to the physical expression or observable trait.

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Homozygous organisms have two identical alleles for a trait (e.g., BBBB or bbbb), while Heterozygous organisms have two different alleles (e.g., BbBb).

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Dominant alleles (denoted by capital letters like RR) mask the expression of recessive alleles (denoted by lowercase letters like rr) in a heterozygous genotype.

📐Formulae

2n=Diploid number of chromosomes2n = \text{Diploid number of chromosomes}

n=Haploid number of chromosomes (gametes)n = \text{Haploid number of chromosomes (gametes)}

Probability of Trait=Number of specific genotypesTotal number of possible offspring×100%\text{Probability of Trait} = \frac{\text{Number of specific genotypes}}{\text{Total number of possible offspring}} \times 100\%

Base Pairing Ratio: [A]=[T] and [C]=[G]\text{Base Pairing Ratio: } [A] = [T] \text{ and } [C] = [G]

💡Examples

Problem 1:

In pea plants, the allele for purple flowers (PP) is dominant over the allele for white flowers (pp). If a heterozygous purple plant (PpPp) is crossed with a white-flowered plant (pppp), what are the expected phenotypic ratios of the offspring?

Solution:

The ratio is 1:11:1 (or 50%50\% Purple and 50%50\% White).

Explanation:

Using a Punnett square for the cross Pp×ppPp \times pp: The possible genotypes are Pp,Pp,pp,ppPp, Pp, pp, pp. There are two PpPp (Purple) and two pppp (White) offspring. This results in a phenotypic ratio of 2:22:2, which simplifies to 1:11:1.

Problem 2:

A sample of DNADNA is analyzed and found to contain 20%20\% Adenine (AA). Calculate the percentage of Cytosine (CC) present in the sample.

Solution:

30%30\%

Explanation:

According to Chargaff's rule, [A]=[T][A] = [T]. Therefore, A=20%A = 20\% and T=20%T = 20\%. Together, A+T=40%A + T = 40\%. The remaining 60%60\% must be shared equally between Guanine and Cytosine because [G]=[C][G] = [C]. Thus, C=60%2=30%C = \frac{60\%}{2} = 30\%.