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Genetics - Chromosomes and Genes

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

DNA (DeoxyribonucleicacidDeoxyribonucleic acid) is the molecule that carries genetic information. It consists of two strands forming a double helix, with a backbone of phosphate and deoxyribose sugar.

The four nitrogenous bases in DNADNA are Adenine (AA), Thymine (TT), Cytosine (CC), and Guanine (GG). They follow complementary base-pairing rules: AA pairs with TT and CC pairs with GG.

Chromosomes are long, coiled structures of DNADNA and proteins (histones) found in the nucleus. Humans typically have 2323 pairs of chromosomes (4646 total).

A gene is a specific segment of DNADNA that codes for a particular protein, which determines a specific trait in an organism.

Alleles are different versions of the same gene (e.g., the gene for eye color may have a blue allele or a brown allele).

Genotype represents the genetic makeup (e.g., AAAA, AaAa, or aaaa), while Phenotype refers to the physical expression or observable trait.

Homozygous organisms have two identical alleles for a trait (e.g., BBBB or bbbb), while Heterozygous organisms have two different alleles (e.g., BbBb).

Dominant alleles (denoted by capital letters like RR) mask the expression of recessive alleles (denoted by lowercase letters like rr) in a heterozygous genotype.

📐Formulae

2n=Diploid number of chromosomes2n = \text{Diploid number of chromosomes}

n=Haploid number of chromosomes (gametes)n = \text{Haploid number of chromosomes (gametes)}

Probability of Trait=Number of specific genotypesTotal number of possible offspring×100%\text{Probability of Trait} = \frac{\text{Number of specific genotypes}}{\text{Total number of possible offspring}} \times 100\%

Base Pairing Ratio: [A]=[T] and [C]=[G]\text{Base Pairing Ratio: } [A] = [T] \text{ and } [C] = [G]

💡Examples

Problem 1:

In pea plants, the allele for purple flowers (PP) is dominant over the allele for white flowers (pp). If a heterozygous purple plant (PpPp) is crossed with a white-flowered plant (pppp), what are the expected phenotypic ratios of the offspring?

Solution:

The ratio is 1:11:1 (or 50%50\% Purple and 50%50\% White).

Explanation:

Using a Punnett square for the cross Pp×ppPp \times pp: The possible genotypes are Pp,Pp,pp,ppPp, Pp, pp, pp. There are two PpPp (Purple) and two pppp (White) offspring. This results in a phenotypic ratio of 2:22:2, which simplifies to 1:11:1.

Problem 2:

A sample of DNADNA is analyzed and found to contain 20%20\% Adenine (AA). Calculate the percentage of Cytosine (CC) present in the sample.

Solution:

30%30\%

Explanation:

According to Chargaff's rule, [A]=[T][A] = [T]. Therefore, A=20%A = 20\% and T=20%T = 20\%. Together, A+T=40%A + T = 40\%. The remaining 60%60\% must be shared equally between Guanine and Cytosine because [G]=[C][G] = [C]. Thus, C=60%2=30%C = \frac{60\%}{2} = 30\%.

Chromosomes and Genes - Revision Notes & Key Formulas | IB Grade 9 Science