Understanding Motion through Experience

If the displacement of an object is proportional to square of time, then the object moves with:

Motion along a straight line is the ______ type of motion.

In everyday life, most of the motions we see are:

The position of a person on a map is usually given relative to:

An object $P$ is being monitored from a fixed reference point $O$. It is observed that at any time $t$, the distance $OP$ is always exactly $10\,m$, but the direction of $P$ relative to $O$ is changing at a constant rate. Which statement correctly evaluates the state of motion of object $P$?

A cruise ship is traveling at a constant speed of $15\,m/s$ due East relative to the water. A seagull is flying at $15\,m/s$ due East relative to the water, directly above the ship. Meanwhile, a passenger is walking on the deck towards the stern (back) of the ship at $2\,m/s$ relative to the deck. Based on the concept of relative motion, which of the following is true?

Which of the following can be calculated by finding the area under a speed-time graph?

The motion of a particle is described by the equation $u = at$. The distance travelled by the particle in the first $4\,s$ is:

A person travels along a straight road for the first half time with a velocity $v_1$ and the next half time with a velocity $v_2$. What is the average velocity of the person?

For a particle moving in a straight line, the displacement $x$ at time $t$ is given by $x = At + Bt^2 - Ct^3$. The acceleration of the particle when its velocity is zero is:

An inertial frame of reference is one in which ________ law of inertia holds true.

To describe the position of an object in a 2D plane, we need:

Which of the following describes the state of a book lying on a table?

A man is walking inside a train in the direction of the train's motion. His speed relative to the ground is:

Can the displacement of an object be different for two different observers?

Which of the following is an example of a relative motion experience?

If you drop a ball in a car that is decelerating (slowing down), where will the ball land relative to the point directly below where it was dropped?

Which of the following remains invariant (unchanged) under Galilean Transformation?

Two trains, each of length $50\, \text{m}$, are running on parallel tracks. One overtakes the other in $20\, \text{seconds}$ and one crosses the other in $10\, \text{seconds}$ when moving in opposite directions. Their speeds are:

A person walks at $1\, \text{m/s}$ on a treadmill moving at $1\, \text{m/s}$ in the opposite direction. The work done by the person relative to the ground is:

The physical quantity which has the same unit as speed is:

Which of the following is a scalar quantity?

If an object moves $10\,m$ to the right and then $10\,m$ to the left, its net displacement is:

A scalar quantity can be completely described by its:

A jogger runs along the perimeter of a regular hexagonal field where each side has a length $L$. If the jogger starts at one vertex and stops after covering exactly half of the total perimeter, what is the magnitude of the jogger's displacement from the starting point?

An automated toy car moves along a track in a warehouse. It starts at point A, travels $8\text{ m}$ North to point B, then $6\text{ m}$ East to point C, and finally $8\text{ m}$ South to point D. Which of the following correctly describes the total distance covered and the magnitude of the net displacement of the toy car?

What is the slope of the velocity-time graph for a body moving with constant velocity?

The ratio of the magnitude of displacement to distance is always:

A particle moves $3\text{ m}$ North, then $4\text{ m}$ East. The magnitude of displacement and the direction are:

A body is moving with uniform velocity $u$. If it is subjected to a constant retardation $a$, it will come to rest after a time $t$. The distance traveled during this time is:

In the graphical method, the scale chosen should be:

If vector $\vec{A}$ is towards North and vector $\vec{B}$ is towards West, the resultant vector $\vec{A} + \vec{B}$ points towards:

To add four vectors graphically using the head-to-tail method, how many arrows are drawn in total including the resultant?

Which of these represents a 'null vector'?

When adding vectors $\vec{A}$, $\vec{B}$, and $\vec{C}$ using the head-to-tail method, the resultant $\vec{R}$ is the vector from:

If two displacement vectors are $10\text{ m}$ each and their resultant is also $10\text{ m}$, what is the angle between the two vectors?

What is the angle between the resultant and vector $\vec{A}$ if $\vec{A}$ and $\vec{B}$ are equal in magnitude and perpendicular to each other?

A physical quantity $X$ is calculated as the vector sum of four other quantities $A, B, C,$ and $D$. If $A, B, C,$ and $D$ are represented by the consecutive sides of a semi-regular octagon, the resultant $X$ is:

A vector $\vec{P}$ when added to $\vec{Q} = 3\hat{i} + 4\hat{j}$ gives a resultant along the y-axis with magnitude 10. Vector $\vec{P}$ is:

A boat can travel at $10\ km/h$ in still water. It crosses a $1\ km$ wide river in 12 minutes by the shortest possible path. The speed of the river flow is:

The three equations of motion are valid only for motion along a:

For a body starting from rest and moving with uniform acceleration, the distance traveled is proportional to:

A body is moving with a uniform velocity of $10 \text{ m/s}$. The acceleration after $10 \text{ s}$ is:

In the equation $v^2 = u^2 + 2as$, if the body starts from rest and $a = 5 \text{ m/s}^2$, $s = 10 \text{ m}$, then $v^2$ is:

An object is moving with a velocity of $10\, m/s$. If it is subjected to a constant retardation of $2\, m/s^2$, how much distance will it travel before its velocity becomes $2\, m/s$?

Two cars A and B start from rest. Car A accelerates at $2\, m/s^2$ and Car B at $4\, m/s^2$. After $5\, s$, the distance between them (if moving in the same direction) is:

A stone is dropped into a well $45\, m$ deep. The sound of splash is heard after $3.125\, s$. If $g = 10\, m/s^2$, what is the speed of sound?

A body starting from rest covers a distance of $9\text{ m}$ in the $5^{th}$ second. The acceleration of the body is:

The displacement of a particle is given by $x = (t-2)^2$ where $x$ is in meters and $t$ in seconds. The distance covered by the particle in the first $4$ seconds is:

A body is thrown vertically upward with velocity $u$. The distance traveled by it in the fifth and the sixth seconds are equal. The velocity $u$ is: (Take $g = 9.8\text{ m/s}^2$)