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Gravitation - Mass and Weight

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Mass is the measure of the quantity of matter contained in an object. It is a scalar quantity and its SI unit is kgkg.

Mass of an object is constant and does not change from place to place. It is also a measure of the inertia of an object.

Weight is the force with which an object is attracted towards the Earth. It is a vector quantity and its SI unit is Newton (NN).

The weight of an object depends on its location because the acceleration due to gravity (gg) varies from place to place (W=mimesgW = m imes g).

On the surface of the Earth, the value of gg is approximately 9.8 m/s29.8 \text{ m/s}^2.

The weight of an object on the Moon is approximately 16\frac{1}{6} of its weight on the Earth because the Moon's gravitational pull is weaker due to its smaller mass and radius.

Mass is measured using a beam balance, while weight is measured using a spring balance.

📐Formulae

W=m×gW = m \times g

g=G×MR2g = \frac{G \times M}{R^2}

Wmoon=16×WearthW_{moon} = \frac{1}{6} \times W_{earth}

1 kg-wt=9.8 N1 \text{ kg-wt} = 9.8 \text{ N}

💡Examples

Problem 1:

Mass of an object is 10 kg10 \text{ kg}. What is its weight on the Earth?

Solution:

W=m×gW = m \times g W=10 kg×9.8 m/s2=98 NW = 10 \text{ kg} \times 9.8 \text{ m/s}^2 = 98 \text{ N}

Explanation:

To find the weight, we multiply the mass of the object by the acceleration due to gravity on Earth (g9.8 m/s2g \approx 9.8 \text{ m/s}^2).

Problem 2:

An object weighs 60 N60 \text{ N} when measured on the surface of the Earth. What would be its weight when measured on the surface of the Moon?

Solution:

Wmoon=16×WearthW_{moon} = \frac{1}{6} \times W_{earth} Wmoon=16×60 N=10 NW_{moon} = \frac{1}{6} \times 60 \text{ N} = 10 \text{ N}

Explanation:

The acceleration due to gravity on the Moon is 16th\frac{1}{6}^{th} of that on the Earth, so the weight of any object becomes 16\frac{1}{6} of its weight on Earth.

Problem 3:

If the mass of a body is 30 kg30 \text{ kg} on Earth, what will be its mass and weight on the Moon? (Take g=9.8 m/s2g = 9.8 \text{ m/s}^2)

Solution:

Mass on Moon =30 kg= 30 \text{ kg}. Weight on Moon: Wmoon=16×(m×gearth)W_{moon} = \frac{1}{6} \times (m \times g_{earth}) Wmoon=16×(30 kg×9.8 m/s2)=49 NW_{moon} = \frac{1}{6} \times (30 \text{ kg} \times 9.8 \text{ m/s}^2) = 49 \text{ N}

Explanation:

Mass remains constant everywhere in the universe. However, weight changes based on the local acceleration due to gravity. The weight on the Moon is calculated by taking one-sixth of the weight on Earth.

Mass and Weight - Revision Notes & Key Formulas | CBSE Class 9 Science