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Physics - Electricity (Static Electricity, Current, Circuits, Heating/Chemical effects)

Grade 8ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Static Electricity: This involves the study of electric charges at rest. Charging an object can occur via friction, conduction, or induction. The fundamental unit of charge is the Coulomb (CC).

Electronic Theory: An atom is electrically neutral. An object becomes positively charged by losing electrons and negatively charged by gaining electrons. The charge of a single electron is approximately 1.6×1019 C-1.6 \times 10^{-19}\ C.

Electric Current (II): It is defined as the rate of flow of electric charge through a conductor. Measured in Amperes (AA).

Potential Difference (VV): The amount of work done in moving a unit positive charge from one point to another. Measured in Volts (VV).

Resistance (RR): The obstruction offered by a conductor to the flow of current. It depends on the material, length, area of cross-section, and temperature. Measured in Ohms (Ω\Omega).

Series Circuit: Components are connected end-to-end. The current (II) remains the same through all components, while the total potential difference (VV) is the sum of individual voltages.

Parallel Circuit: Components are connected across the same two points. The potential difference (VV) remains the same, while the total current (II) is the sum of currents through individual branches.

Heating Effect of Current: When current passes through a high-resistance wire (like Nichrome), electrical energy is converted into heat energy. This is governed by Joule's Law: H=I2RtH = I^2Rt.

Chemical Effect of Current: The passage of electric current through a conducting solution (electrolyte) causes chemical reactions. Key processes include electrolysis and electroplating. Cations (++) move toward the Cathode (-) and Anions (-) move toward the Anode (++).

Safety Devices: An electric fuse is a safety device with a low melting point that breaks the circuit during overloading or short-circuiting.

📐Formulae

Q=n×eQ = n \times e

I=QtI = \frac{Q}{t}

V=WQV = \frac{W}{Q}

V=I×RV = I \times R

Rs=R1+R2+R3+R_s = R_1 + R_2 + R_3 + \dots

1Rp=1R1+1R2+1R3+\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \dots

H=I2RtH = I^2Rt

P=V×IP = V \times I

💡Examples

Problem 1:

Calculate the current flowing through a conductor if a charge of 450 C450\ C passes through it in 22 minutes.

Solution:

Given: Charge Q=450 CQ = 450\ C, Time t=2 minutes=2×60=120 st = 2\text{ minutes} = 2 \times 60 = 120\ s. Using the formula I=QtI = \frac{Q}{t}, we get I=450120=3.75 AI = \frac{450}{120} = 3.75\ A.

Explanation:

To find the current, the time must be converted from minutes to the SI unit of seconds before applying the formula I=QtI = \frac{Q}{t}.

Problem 2:

Two resistors of 6 Ω6\ \Omega and 12 Ω12\ \Omega are connected in parallel. Calculate their equivalent resistance.

Solution:

Given: R1=6 ΩR_1 = 6\ \Omega and R2=12 ΩR_2 = 12\ \Omega. In parallel: 1Rp=1R1+1R21Rp=16+112=2+112=312=14\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} \Rightarrow \frac{1}{R_p} = \frac{1}{6} + \frac{1}{12} = \frac{2+1}{12} = \frac{3}{12} = \frac{1}{4}. Therefore, Rp=4 ΩR_p = 4\ \Omega.

Explanation:

In a parallel circuit, the reciprocal of the total resistance is the sum of the reciprocals of individual resistances. The effective resistance is always less than the smallest individual resistance.

Problem 3:

An electric heater of resistance 50 Ω50\ \Omega draws a current of 5 A5\ A. Calculate the heat produced in 1010 seconds.

Solution:

Given: R=50 ΩR = 50\ \Omega, I=5 AI = 5\ A, t=10 st = 10\ s. Using Joule's Law: H=I2Rt=(5)2×50×10=25×50×10=12,500 JH = I^2Rt = (5)^2 \times 50 \times 10 = 25 \times 50 \times 10 = 12,500\ J.

Explanation:

The heat produced is directly proportional to the square of the current, the resistance, and the time for which the current flows.

Electricity (Static Electricity, Current, Circuits, Heating/Chemical effects) Revision - Class 8…